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vodomira [7]
3 years ago
13

Solve for x. Need help, Thank you!! Also, i need explanation.

Mathematics
1 answer:
babunello [35]3 years ago
4 0

Answer:

7.) x = 12

9.) x = 4

Step-by-step explanation:

7.) Angle Y and Angle X both add up to 180

=> 40 + 12x - 4 = 180

=> 36 + 12x = 180

=> 12x = 180 - 36

=> 12x = 144

=> x = 12

9.) Angle W and Angle X add up to 180

=> 145 + (-1) + 9x = 180

=> 144 + 9x = 180

=> 9x = 180 - 144

=> 9x = 36

=> x = 36 / 9

=> x = 4

Hope this helps!

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Guys omg please someone answer this asap this is due tmmr
MrRissso [65]

Answer:

First, break the shape into smaller shapes.

Bigger rectangle: 5m, 8m

Thin rectangle: 7m, 3m

Thinner rectangle: 8m, 2m

We will call the bigger rectangle <u>B</u>, the thin rectangle <u>R</u>, and the thinner rectangle <u>r</u>.

Step-by-step explanation:

B = 8 • 5 = 40

R = 7 • 3 = 21

r = 2 • 8 = 16

Add the areas together:

40 + 21 + 16 = 77

Therefore, the area is <u>77 meters.</u>

4 0
2 years ago
Statistics In the manual “How to Have a Number One the Easy Way,” it is stated that a song “must be no longer than three minutes
dimaraw [331]

Answer:

We conclude that the sample is from a population of songs with a mean greater than 210 seconds.

Step-by-step explanation:

We are given that a simple random sample of 40 current hit songs results in a mean length of 252.5 seconds.

Assume that the standard deviation of song lengths is 54.5 sec.

Let \mu = <u><em>population mean length of the songs</em></u>

So, Null Hypothesis, H_0 : \mu \leq 210 seconds      {means that the sample is from a population of songs with a mean smaller than or equal to 210 seconds}

Alternate Hypothesis, H_A : \mu > 210 seconds      {means that the sample is from a population of songs with a mean greater than 210 seconds}

The test statistics that will be used here is <u>One-sample z-test statistics </u>because we know about population standard deviation;

                              T.S.  =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean length of songs = 252.5 seconds

            \sigma = population standard deviation = 54.5 seconds

            n = sample of current hit songs = 40

So, <u><em>the test statistics</em></u> =  \frac{252.5-210}{\frac{54.5}{\sqrt{40} } }

                                   =  4.932

The value of z-test statistics is 4.932.

Now, at 0.05 level of significance, the z table gives a critical value of 1.645 for the right-tailed test.

Since the value of our test statistics is more than the critical value of z as 4.932 > 1.645, so <u><em>we have sufficient evidence to reject our null hypothesis</em></u> as it will fall in the rejection region.

Therefore, we conclude that the sample is from a population of songs with a mean greater than 210 seconds.

4 0
3 years ago
I need help answering
irga5000 [103]
For this equation, all you need to do is plug in the numbers to the equation...
(3/2)6 - 3 + (5/3)3
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(18/2) - 3 + (15/3)
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Then subtract and add...
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3 years ago
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EleoNora [17]

Answer:

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Step-by-step explanation:

If k equals -67 the answer would be 73.

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