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Contact [7]
3 years ago
9

Presley is marking the lines for a soccer field. She needs to form a right triangle near the goal. She measures the lengths of h

er sides as 9 yards, 6 yards and √45 yards. Did Presley form a right triangle? Why? Yes, because 6 squared + 9 squared = (startRoot 45 EndRoot) squared Yes, because 6 squared + (StartRoot 45 EndRoot) squared = 9 squared No, because 6 squared + 9 squared not-equals (StartRoot 45 EndRoot) Squared No, because 6 squared + (StartRoot 45 EndRoot) squared not-equals 9 squared
Mathematics
2 answers:
Hunter-Best [27]3 years ago
8 0

Answer:it’s b

Step-by-step explanation:

inessss [21]3 years ago
7 0

Answer:

B

Step-by-step explanation:

Yes, because 6 squared + (StartRoot 45 EndRoot) squared = 9 squared

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Find the midpoint of the line segment with the endpoints (1, 0) and (2, -10).
Mariulka [41]

Answer:

\bigl(\frac{3}{2},-5\bigr)

or in decimal form

(1.5,-5)

Step-by-step explanation:

The midpoint of the line with endpoints (x_1,y_1) and (x_2,y_2) is \bigl(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\bigr). just take the average between the points

so given the points (1,0) and (2,-10)

x_1=1

y_1=0

x_2=2

y_2=-10

the midpoint is found as follows:

\bigl(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\bigr)

\bigl(\frac{1+2}{2},\frac{0-10}{2}\bigr)

\bigl(\frac{3}{2},\frac{-10}{2}\bigr)

\bigl(\frac{3}{2},-5\bigr)

or in decimal form

(1.5,-5)

7 0
3 years ago
Find the distance between the following points: (0,0,0) and (-2,6,3)
marusya05 [52]

9514 1404 393

Answer:

  3.  7

Step-by-step explanation:

The distance formula applies in 3 dimensions as well as 2.

  d = √((x2 -x1)² +(y2 -y1)² +(z2 -z1)²)

  d = √((-2)² +6² +3²) = √(4 +36 +9) = √49

  d = 7

The distance between the two points is 7 units.

6 0
2 years ago
How many significant figures is in 0.040060?
nadezda [96]

Answer: Sig Figs 5

Step-by-step explanation:

3 0
3 years ago
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The inverse of the following function is also a function.<br><br> True<br><br> False
dybincka [34]
I think that’s true
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3 years ago
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Calculate the probability of needing at least 5 tosses of an unbiased coin to land a head.
Gnom [1K]

Answer:

0.03125

Step-by-step explanation:

If we have a fair coin the probability of landing a head is 50%.

We can think the question as what is the probability of landing four tails and then a head. That is we needed at least 5 tries to get a head.

Prob \{ T,T,T,T,H\}

Since this events are independent we can write it as

Prob \{ T\} \times Prob \{ T\} \times Prob \{ T\} \times Prob \{ T\} \times Prob \{ H\} =.5^5= 0.03125

4 0
2 years ago
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