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Svetlanka [38]
3 years ago
12

100 POINTS AND BRAINLY

Mathematics
2 answers:
eduard3 years ago
8 0

Answer:

 \mathsf{\sin T=\dfrac{t}{v} \ \ \ \cos T=\dfrac{u}{v}}\\\\\mathsf{\cos U=\dfrac{t}{v} \ \ \ \sin U=\dfrac{u}{v}}

Step-by-step explanation:

Trig ratios:

\mathsf{\sin(\theta)=\dfrac{O}{H} \ \ \ \cos(\theta)=\dfrac{A}{H} \ \ \ \tan(\theta)=\dfrac{O}{A}}

(where \theta is the angle, O is the side opposite the angle, A is the side adjacent the angle and H is the hypotenuse of a right triangle)

\mathsf{\sin T=\dfrac{t}{v} \ \ \ \cos T=\dfrac{u}{v}}\\\\\mathsf{\cos U=\dfrac{t}{v} \ \ \ \sin U=\dfrac{u}{v}}

katrin2010 [14]3 years ago
6 0

Answer:

  • Given and Explained Below.

Explanation:

  • \sf sin(x)= \dfrac{opposite}{hypotensue}
  • \sf cos(x)= \dfrac{adjacent}{hypotensue}
  • \sf tan(x)= \dfrac{opposite}{adjacent}

<u>using the formula's:</u>

<u />\sf sin(T)= \dfrac{t}{v}

\sf cos(T)= \dfrac{u}{v}

\sf cos(U)= \dfrac{t}{v}

\sf sin(U)= \dfrac{u}{v}

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