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aniked [119]
3 years ago
14

Hepl with polynomials (2/3Y2 - 3/4) + (5/6Y2 + 4)

Mathematics
1 answer:
hodyreva [135]3 years ago
5 0
4y/3 - 3/4 + 5/6y (multiply by) x 2 + 4

4y/3 - 3/4 + 5y/3 + 4

collect like terms: (4y/3 + 5y/3)  +  ( - 3/4 + 4)

simplify:  3y + 13/4      <----- FINAL ANSWER
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Components arriving at a distributor are checked for defects by two different inspectors (each component is checked by both insp
Yuliya22 [10]

Complete question is;

Components arriving at a distributor are checked for defects by two different inspectors (each component is checked by both inspectors). The first inspector detects 83% of all defectives that are present, and the second inspector does likewise. At least one inspector does not detect a defect on 34% of all defective components. What is the probability that the following occurs?

(a) A defective component will be detected only by the first inspector?

b) A defective component will be detected by exactly one of the two inspectors?

(c) All three defective components in a batch escape detection by both inspectors (assuming inspections of different components are independent of one another)?

Answer:

A) 0.17

B) 0.34

C) 0

Step-by-step explanation:

a) We are told that the first inspector(A) detects 83% of all defectives that are present, and the second inspector(B) also does the same.

This means that;

P(A) = P(B) = 83% = 0.83

We are also told that at least one inspector does not detect a defect on 34% of all defective components.

Thus;

P(A' ⋃ B') = 0.34

Also, we now that;

P(A ⋂ B) = 1 - P(A' ⋃ B')

P(A ⋂ B) = 1 - 0.34

P(A ⋂ B) = 0.66

Probability that A defective component will be detected only by the first inspector is;

P(A ⋂ B') = P(A) - P(A ⋂ B)

P(A ⋂ B') = 0.83 - 0.66

P(A ⋂ B') = 0.17

B) probability that a defective component will be detected by exactly one of the two inspectors is given as;

P(A ⋂ B') + P(A' ⋂ B) = P(A) + P(B) - 2P(A ⋂ B)

P(A) + P(B) - 2P(A ⋂ B) ; 0.83 + 0.83 - 2(0.66) = 0.34

C) Probability that All three defective components in a batch escape detection by both inspectors is written as;

P(A' ⋃ B') - (P(A ⋂ B') + P(A' ⋂ B))

Plugging in the relevant values, we have;

0.34 - 0.34 = 0

7 0
3 years ago
If an increase in one variable causes a decrease in another​ variable, there is A. a negative relationship. B. a dependent relat
Lunna [17]

Answer: Option 'A' is correct.

Step-by-step explanation:

Since we have given a situation that

If an increase in one variable causes a decrease in another​ variable,

Then, there is inverse relationship.

When one variable is increased whereas other variable falls.

There will be inverse relationship.

Since inverse relation has negative relation.

Then, there is a negative relationship.

Hence, Option 'A' is correct.

7 0
3 years ago
Someone help me? Fifth grade simplifying fractions
Delvig [45]

Answer:sure so all you have to do it multluping and sutract easy

Step-by-step explanation:


4 0
3 years ago
Read 2 more answers
18. What is the y-intercept of the line that passes<br> through the points (1, 1) and (5, 13)?
TEA [102]

Answer:

-2

(The coordinate point is (0,-2))

Step-by-step explanation:

First, make an equation of the line.

Start off with finding the slope:

Slope = (13-1)/(5-1) = 12/4 = 3

Then solve for the y-intercept though substitution and simplification:

y=mx+b --> 1=3(1)+b --> 1=3+b --> b= -2

So the answer is -2.

4 0
3 years ago
Which of the angles in the figure are supplementary to 7?
ira [324]
Number D is the correct answer I think
3 0
2 years ago
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