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mixas84 [53]
3 years ago
7

What is 11 m to the -5 power

Mathematics
1 answer:
sertanlavr [38]3 years ago
6 0

Answer:

On simplifying  11 m to the -5  , we get: (\frac{1}{161051 \times m^5})

Step-by-step explanation:

As we know by the law of EXPONENTS:

a ^{(-m)}  = \frac{1}{a^m}

Also, by the Power, w e get: (a)^m = a \times a  \times a ....... m times

Here, using the same we find the value of : (11m)^{(-5)}, we get:

(11m)^{( -5)}  = \frac{1}{(11m)^5}  = \frac{1}{11m \times 11m \times 11m \times 11m \times 11m}  = \frac{1}{161051 \times m^5} \\\implies  (11m)^{( -5)}  =  \frac{1}{161051 \times m^5}

Hence, on simplifying  11 m to the -5  , we get: (\frac{1}{161051 \times m^5})

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And

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3 years ago
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3 0
3 years ago
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Leya [2.2K]

Answer:

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  (b) 248 square units

Step-by-step explanation:

<u>(a) left sum</u>

See the attachment for a diagram of the areas being summed (in orange). This is the sum of the first 4 table values for f(x), each multiplied by 2 (the width of the rectangle). Quite clearly, the curve is above the rectangle for the entire interval, so the rectangle area underestimates the area under the curve.

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<u>(b) right sum</u>

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▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ { \huge \mathfrak{Answer}}▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪

Given :

f(x) =  {x}^{3}  + 2 {x}^{2}  + 3x + 1

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let's solve for f(x) × g(x) :

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