Answer:
10.82 m
Step-by-step explanation:
Length of ladder (L) = 15.5 m
Degree with the horizontal (θ) = 44°15'=44.25°
This problem can be interpreted as a right triangle with L being the hypotenuse. The distance 'd' the ladder goes up the wall is the side opposite to the given angle. Therefore, the sine property can be used to find 'd':
The distance that the ladder goes up the wall is roughly 10.82 m.
Answer:
You answered it yourself but its 5?
Dude, what kind of question is this??? Here's my best shot.
If they start at the 32-mile mark, then the we can use 32 as the intercept. 50 can be the change in position over time, so
y=50x+32 (?)
Answer:
2x(sinx^2 + x^2cosx^2).
Step-by-step explanation:
We use the product rule:
If u and v are functions of x then:-
d(uv)/dx = u dv/dx + v du/dx
So:
d(x^2 sinx^2)dx
= x^2 * d(sinx^2)/dx + sinx^2 * d(x^2)/dx
= x^2 * 2xcosx^2 + sinx^2 * 2x
= 2x^3cosx^2 + 2xsinx^2
= 2x(sinx^2 + x^2cosx^2).
The fraction 4/5 is equivalent to 0.8 and 80%.
Write 0.8 and 80% as unreduced fractions.
0.8 = 8/10
80% = 80/100