These are two questions and two answers.
Question 1) Which of the following polar equations is equivalent to the parametric equations below?
<span>
x=t²
y=2t</span>
Answer: option <span>A.) r = 4cot(theta)csc(theta)
</span>
Explanation:
1) Polar coordinates ⇒ x = r cosθ and y = r sinθ
2) replace x and y in the parametric equations:
r cosθ = t²
r sinθ = 2t
3) work r sinθ = 2t
r sinθ/2 = t
(r sinθ / 2)² = t²
4) equal both expressions for t²
r cos θ = (r sin θ / 2 )²
5) simplify
r cos θ = r² (sin θ)² / 4
4 = r (sinθ)² / cos θ
r = 4 cosθ / (sinθ)²
r = 4 cot θ csc θ ↔ which is the option A.
Question 2) Which polar equation is equivalent to the parametric equations below?
<span>
x=sin(theta)cos(theta)+cos(theta)
y=sin^2(theta)+sin(theta)</span>
Answer: option B) r = sinθ + 1
Explanation:
1) Polar coordinates ⇒ x = r cosθ, and y = r sinθ
2) replace x and y in the parametric equations:
a) r cosθ = sin(θ)cos(θ)+cos(θ)
<span>
b) r sinθ =sin²(θ)+sin(θ)</span>
3) work both equations
a) r cosθ = sin(θ)cos(θ)+cos(θ) ⇒ r cosθ = cosθ [ sin θ + 1] ⇒ r = sinθ + 1
<span>
b) r sinθ =sin²(θ)+sin(θ) ⇒ r sinθ = sinθ [sinθ + 1] ⇒ r = sinθ + 1
</span><span>
</span><span>
</span>Therefore, the answer is r = sinθ + 1 which is the option B.
Answer:
it wold be A
Step-by-step explanation:
Answer:
n = 18
Step-by-step explanation:
The formula for angle sum of a polygon is S = 180 (n - 2), where S is the sum and n is the sides.
We are given that the sum is 2880, and are trying to find n.
Simply sub in S = 2880,
2880 = 180 (n - 2)
Divide by 180 to get (n - 2) by themselves on the right side,
16 = n - 2
Now add 2 to the other side to get n by itself
18 = n
n = 18
Hope this helped!! Please feel free to ask me if there's anything you don't understand from this working
Answer
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-12m -3 + 4m + 16 = 29m
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3+13-5p-2p =9p
I think these are the answers please don’t get mad if they are not hope I help :)
150. Divide 5000 by 100 and you get 50. Multiply 3 by 50 and you get 150.
