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Charra [1.4K]
3 years ago
5

What is 6/8/ divided by 5/7

Mathematics
2 answers:
ziro4ka [17]3 years ago
8 0

Answer:

6/8 divided by 5/7 is 1.05/ 1 1/20

kondor19780726 [428]3 years ago
5 0

Step-by-step explanation:

do same change flip leave 6/8 the same then put × and flip 7/5 and it = 42/40 and u reduce it bye 2 =21/20 thats ur answer

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Solve the following equation:
Rama09 [41]

Complete the square.

z^4 + z^2 - i\sqrt 3 = \left(z^2 + \dfrac12\right)^2 - \dfrac14 - i\sqrt3 = 0

\left(z^2 + \dfrac12\right)^2 = \dfrac{1 + 4\sqrt3\,i}4

Use de Moivre's theorem to compute the square roots of the right side.

w = \dfrac{1 + 4\sqrt3\,i}4 = \dfrac74 \exp\left(i \tan^{-1}(4\sqrt3)\right)

\implies w^{1/2} = \pm \dfrac{\sqrt7}2 \exp\left(\dfrac i2 \tan^{-1}(4\sqrt3)\right) = \pm \dfrac{2+\sqrt3\,i}2

Now, taking square roots on both sides, we have

z^2 + \dfrac12 = \pm w^{1/2}

z^2 = \dfrac{1+\sqrt3\,i}2 \text{ or } z^2 = -\dfrac{3+\sqrt3\,i}2

Use de Moivre's theorem again to take square roots on both sides.

w_1 = \dfrac{1+\sqrt3\,i}2 = \exp\left(i\dfrac\pi3\right)

\implies z = {w_1}^{1/2} = \pm \exp\left(i\dfrac\pi6\right) = \boxed{\pm \dfrac{\sqrt3 + i}2}

w_2 = -\dfrac{3+\sqrt3\,i}2 = \sqrt3 \, \exp\left(-i \dfrac{5\pi}6\right)

\implies z = {w_2}^{1/2} = \boxed{\pm \sqrt[4]{3} \, \exp\left(-i\dfrac{5\pi}{12}\right)}

3 0
1 year ago
Please answer correctly ! Will mark brainliest !!!
Black_prince [1.1K]

Answer:

A  

Step-by-step explanation:

7 0
2 years ago
The final velocity V of an object
Alekssandra [29.7K]

Answer:

The final velocity, V, of an object under constant acceleration can be found using the formula V2=v2+2as , where v is the initial velocity in meters per second, a is acceleration in meters per second, and s is the distance in meters.

7 0
2 years ago
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In triangle ABC, the measure of angle B is 90 degrees, BC=16, and AC=20. triangle DEF is similar to triangle ABC, where vertices
kkurt [141]
 <span>The third side of triangle ABC is AB. Using the Pythagorean Theorem, its length is 12. 
12² + 16² = 20² 

∠F is congruent to ∠C and so the sin(∠F) = sin(∠C) 

The sin(∠C) = opposite/hypotenuse 
= |AB| / |AC| 
= 12/20 
= 3/5 
= 0.6 

So the answer is 0.6.</span>
6 0
3 years ago
Find the area of an isosceles trapezoid, if the lengths of its bases are 16 cm, and 30 cm, and the diagonals are perpendicular t
Klio2033 [76]
For this case we have:
 a = 30 cm
 c = 16 cm
 We look for the length of the diagonal:
 d = x + y
 Where,
 For x:
 a ^ 2 = x ^ 2 + x ^ 2
 x = a / root (2) = 30 / root (2) = 21.2132 cm
 For y:
 c ^ 2 = y ^ 2 + y ^ 2
 y = c / root (2) = 16 / root (2) = 11.3137 cm
 The diagonal is:
 d = x + y
 d = 21.2132 + 11.3137
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 Then, the height is:
 h = h1 + h2
 For h1:
 h1 = root (x ^ 2 - (a / 2) ^ 2) = root ((21.2132) ^ 2 - (30/2) ^ 2)
 h1 = 15 cm
 For h2:
 h2 = root (y ^ 2 - (c / 2) ^ 2) = root ((11.3137) ^ 2 - (16/2) ^ 2)
 h2 = 8 cm
 Finally:
 h = h1 + h2
 h = 15 + 8
 h = 23 cm
 Then, the area is:
 A = (1/2) * (a + c) * (h)
 A = (1/2) * (30 + 16) * (23)
 A = 529 cm ^ 2
 Answer:
 
the area of an isosceles trapezoid is:
 
A = 529 cm ^ 2
4 0
2 years ago
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