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son4ous [18]
3 years ago
14

The graph of a function is shown on the coordinate plane below. Identify the rate of change of the function.

Mathematics
1 answer:
Irina18 [472]3 years ago
6 0

Answer:

5/4

Step-by-step explanation:

Rise over run you go up 5 and left 4 so 5/4 is the ROC.

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What expression is equivalent to 5n+6+(-7n)
tensa zangetsu [6.8K]
You just have to simplify:
-2n+6
8 0
3 years ago
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The slope of the line below is -2. Use the coordinates of the labeled point to
Vilka [71]

Answer:

We can express the equation for any linear equation with slope -2 and point (x0,y0) as:

y=-2x+(y_0+2x_0)\\\\y-y_0=-2(x-x_0)

Step-by-step explanation:

Incomplete question:

There is no point to complete the equation.

As we have no point to complete the linear equation, we will solve for any given point (x0,y0) and a slope of m=-2.

The linear equation can be written generically as:

y(x)=mx+b\\\\y(x)=-2x+b

If a point, like (x0,y0) belongs to the linear equation, it satisfies its equation. Then:

y_0=-2x_0+b

Then, we can calculate b as:

y_0=-2x_0+b\\\\b=y_0+2x_0

We can express the equation for any linear equation with slope -2 and point (x0,y0) as:

y=-2x+(y_0+2x_0)\\\\y-y_0=-2(x-x_0)

6 0
3 years ago
Solve
Strike441 [17]

Answer:

x=±\sqrt{15/2}

Step-by-step explanation:

8 0
3 years ago
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PLEASE HELP ASAP ON MY MATH!!
Allisa [31]

Answer:

Area of shaded region=41 square feet

Area of non shaded region= 87 square feet

Step-by-step explanation:

As, Shaded area is made of different shapes including two rectangles and one triangle

So,

Area of shaded region,

=(8\times2)+(10\times 1)+(\frac{1}{2}\times 3\times10)\\\\ =16+10+15=41 \quad \text{square feet}

Area of non shaded region=total area of rectangular region-Shaded region

=(16\times 8)-(41)\\=128-41\\=87 \quad \text{square feet}

7 0
2 years ago
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Circle a has a radius of 3 and circle b has a radius of 11. if the idstance between the center of the circles in 17, find the le
Andrews [41]
Use Pythagorean Theorem:
a² + b² = c²
"a" is one side of the right triangle.
Its length is: radius of larger circle minus radius of smaller circle: (11 - 3 = 8)
The distance between the center of the circles creates the hypotenuse (17)
8² + b² = 17²
       b² = 225
       b = 15

Answer: the length of the common external tangent is 15.

3 0
3 years ago
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