Answer:
3)
4) a)
b)
Step-by-step explanation:
<u>Exercise 3</u>
<u>Exercise 4</u>
a) If L2 is parallel to L1, it has the same slope (gradient) ⇒
If L2 passes through point (3, 1):
So L2 = L1
b) If L3 is perpendicular to L1, then the slope of L3 is the negative reciprocals of the slope of L1 ⇒
If L3 passes through point (-5, 2):
(a)
We can see that
this is a straight line
and this is the graph of velocity
we know that
acceleration is the derivative of velocity
so, slope of curve of velocity is acceleration
so, we will find slope of this line
We can select any two points
(0,4) and (5,7)
we can use slope formula
now, we can plug points
we know that slope of line is always constant irrespective of any value of t
so, acceleration will always be same irrespective of any value of t
so, we will get acceleration
............Answer
(b)
we can see that acceleration is constant
and we know that
derivative of constant is always 0
so, instantaneous rate of acceleration at t=10s is 0........Answer
