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4 years ago

12

A freshman drops his net to a depth of -8 feet below the surface of the water. How far does he need to raise the net to bring it

back tonthe ground

1 answer:

harina [27]4 years ago

5 0

Wouldn't it be 8 feet because if it is 8 feet below the surface of the water raise it 8 feet and its on the surface.

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Students are making the scenery for a school play. They use a large piece of plywood to represent the front of a house, with a s

Vera_Pavlovna [14]

Considering the figures, the area that will be painted is of 38.9 square feet.

<h3>What is the area of a rectangle?</h3>

The area of a rectangle of length l and width w is given by:

$A = lw$

<h3>What is the area of a triangle?</h3>

The area of a triangle of base b and height h is given by:

$A = \frac{bh}{2}$

<h3>What is the area of a semi-circle?</h3>

The area of a semi-circle of radius r is given by:

$A = 0.5\pi r^2$

In this problem:

The rectangle with l = 6 ft and w = 8 ft will be painted, along with the triangle of dimensions b = 8 ft and h = 4 ft.

The semi-circle with r = 4 ft will not be painted.

Hence, the area that will be painted, in square feet, is given by:

$A = 6 \times 8 + \frac{8(4)}{2} - 0.5\pi 4^2 = 64 - 8\pi = 38.9$

More can be learned about the area of a figure at brainly.com/question/10489198

3 0

3 years ago

If there is a maximum of 4,000 hours of labor available per month and 300 ping-pong balls (x1) or 125 wiffle balls (x2) can be p

andrey2020 [161]

Answer:

b. 300x1 + 125x2 < = 4,000

Step-by-step explanation:

Maximum of 4,000 hours

This means that the the total amount of labor has to be of at most 4,000, that is:

$T \leq 4000$

300 ping-pong balls (x1) or 125 wiffle balls (x2) can be produced per hour of labor

The total amount of labor is:

$T = 300x1 + 125x2$

Uniting the two equations:

$T \leq 4000$

$300x1 + 125x2 \leq 4000$

And thus the correct answer is given by option b.

6 0

3 years ago

What is the slope of a line parallel to the line whose equation is 3 x + 3 y = − 27 3x+3y=−27.

Nata [24]

the answer is y=-1/1x-9 so the slope is -1 over 1

4 0

3 years ago

if x and y are the tens digit and the units digit, respectively, of the product 725,278x67,066, what is the value of x+y? The an

topjm [15]

725,278 * 67,066 = 48641494348....now, if x is in the 10 digits spot...it is 4...and if y is in the units spot, then it is 8.....
x + y = 4 + 8 = 12

6 0

3 years ago

The shark are fed three times a day during the morning feeding 2/15 of a ton. During the afternoon feeding the weight of fish fe

UNO [17]

Answer:

The shark are fed $\frac16 \ ton$ of fish during the night.

Step-by-step explanation:

Given:

Weight of fish fed in the morning = $\frac{2}{15}\ ton$

Also Given:

During the afternoon feeding the weight of fish fed will be 1/15 of a ton more than the fish fed during the morning.

Weight of fish fed in the afternoon = $\frac{2}{15}+\frac{1}{15}=\frac{2+1}{15}=\frac{3}{15}\ ton$

Total fish fed in whole day = $\frac12 \ ton$

We need to find the Weight of fish fed in the night.

Solution:

Now we can say that;

Weight of fish fed in the night can be calculated by by subtracting Weight of fish fed in the morning and Weight of fish fed in the afternoon from Total fish fed in whole day .

framing in equation form we get;

Weight of fish fed in the night = $\frac{1}{2}-\frac{2}{15}-\frac{3}{15}= \frac{1}{2}-(\frac{2}{15}+\frac{3}{15})=\frac{1}{2}-\frac{2+3}{15}= \frac{1}{2}-\frac{5}{15} = \frac{1}{2}-\frac{1}{3}$

Now we will use LCM for making the denominator common we get;

Weight of fish fed in the night = $\frac{1\times3}{2\times3}-\frac{1\times2}{3\times2} = \frac{3}{6}-\frac{2}{6}$

Now denominator are common so we will solve the numerators.

Weight of fish fed in the night = $\frac{3-2}{6}=\frac16 \ ton$

Hence The shark are fed $\frac16 \ ton$ of fish during the night.

3 0

3 years ago