Treat x^4 as the square of p: x^4 = p^2.
Then x^4 - 5x^2 - 36 = 0 becomes p^2 - 5p - 36 = 0.
This factors nicely, to (p-9)(p+4) = 0. Then p = 9 and p = -4.
Equating 9 and x^2, we find that x=3 or x=-3.
Equating -4 and x^2, we see that there's no real solution.
Show that both x=3 and x=-3 are real roots of x^4 - 5x^2 - 36 = 0.
Answer:
option D

Step-by-step explanation:
Given in the question an expression,

Step 1
Divide and multiple by
to remove radical sign from denominator.

Step 2
Apply a² - b² = (a+b)(a-b)

Step 3

Step 4

Step 5

The distance between point M and point is is about 8.06 units (rounded to nearest hundredth)
I believe it would be B observational sampling
Answer:

General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS<u>
</u>
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
- Coordinates (x, y)
- Slope Formula:

Step-by-step explanation:
<u>Step 1: Define</u>
Point (2, 5)
Point (-3, 7)
<u>Step 2: Identify</u>
x₁ = 2, y₁ = 5
x₂ = -3, y₂ = 7
<u>Step 3: Find slope </u><em><u>m</u></em>
Simply plug in the 2 coordinates into the slope formula to find slope<em> m</em>
- Substitute in points [Slope Formula]:

- [Slope] [Fraction] Subtract:

- [Slope] [Fraction] Rewrite:
