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wolverine [178]

3 years ago

10

lee and maya are collecting leaves for an art project. lee collects 24-100 of the total leaves needed. maya collects 4-10 of the

total leaves needed. What fraction of the total number leaves did they collect altogether

1 answer:

tiny-mole [99]3 years ago

6 0

Answer:

16/25

Step-by-step explanation:

4/10=40/100

24/100=24/100

40+24=64

64/100

16/25

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Can someone help fast please

Phoenix [80]

Answer:

$\frac{3a}{a-2}$

Step-by-step explanation:

$\frac{2a - 7}{a}*\frac{3a^2}{2a^2 - 11a + 14}$

Factorise $2a^2 - 11a + 14}$

$\frac{2a - 7}{a}*\frac{3a^2}{(2a - 7)(a - 2)}$

$2a - 7$ cancels 2a - 7

$\frac{1}{a}*\frac{3a^2}{(1))(a - 2)}$

$\frac{1(3a^2)}{a(a-2)}$

$\frac{a(3a)}{a(a-2)}$

"a" cancels "a"

$\frac{3a}{a-2}$

Thus,

$\frac{2a - 7}{a}*\frac{3a^2}{2a^2 - 11a + 14}$ = $\frac{3a}{a-2}$

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pychu [463]

Answer:

use the explicit rule

Step-by-step explanation:

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3 years ago

An individual repeatedly attempts to pass a driving test. Suppose that the probability of passing the test with each attempt is

vladimir1956 [14]

Answer:

a) Our random variable X="number of tests taken until the individual passes" follows a geomteric distribution with probability of success p=0.25

For this case the probability mass function would be given by:

$P(X= k) = (1-p)^{k-1} p , k = 1,2,3,...$

b) $P(X \leq 3) = P(X=1) +P(X=2) +P(X=3)$

$P(X= 1) = (1-0.25)^{1-1} *0.25 = 0.25$

$P(X= 2) = (1-0.25)^{2-1} *0.25 = 0.1875$

$P(X= 3) = (1-0.25)^{3-1} *0.25 = 0.1406$

And adding the values we got:

$P(X \leq 3) =0.25+0.1875+0.1406=0.578$

c) $P(X \geq 5) = 1-P(X$

And we can find the individual probabilities:

$P(X= 1) = (1-0.25)^{1-1} *0.25 = 0.25$

$P(X= 2) = (1-0.25)^{2-1} *0.25 = 0.1875$

$P(X= 3) = (1-0.25)^{3-1} *0.25 = 0.1406$

$P(X= 4) = (1-0.25)^{4-1} *0.25 = 0.1055$

$P(X \geq 5) = 1-[0.25+0.1875+0.1406+0.1055]= 0.316$

Step-by-step explanation:

Previous concepts

The geometric distribution represents "the number of failures before you get a success in a series of Bernoulli trials. This discrete probability distribution is represented by the probability density function:"

$P(X=x)=(1-p)^{x-1} p$

Let X the random variable that measures the number of trials until the first success, we know that X follows this distribution:

$X\sim Geo (1-p)$

Part a

Our random variable X="number of tests taken until the individual passes" follows a geomteric distribution with probability of success p=0.25

For this case the probability mass function would be given by:

$P(X= k) = (1-p)^{k-1} p , k = 1,2,3,...$

Part b

We want this probability:

$P(X \leq 3) = P(X=1) +P(X=2) +P(X=3)$

We find the individual probabilities like this:

$P(X= 1) = (1-0.25)^{1-1} *0.25 = 0.25$

$P(X= 2) = (1-0.25)^{2-1} *0.25 = 0.1875$

$P(X= 3) = (1-0.25)^{3-1} *0.25 = 0.1406$

And adding the values we got:

$P(X \leq 3) =0.25+0.1875+0.1406=0.578$

Part c

For this case we want this probability:

$P(X \geq 5)$

And we can use the complement rule like this:

$P(X \geq 5) = 1-P(X$

And we can find the individual probabilities:

$P(X= 1) = (1-0.25)^{1-1} *0.25 = 0.25$

$P(X= 2) = (1-0.25)^{2-1} *0.25 = 0.1875$

$P(X= 3) = (1-0.25)^{3-1} *0.25 = 0.1406$

$P(X= 4) = (1-0.25)^{4-1} *0.25 = 0.1055$

$P(X \geq 5) = 1-[0.25+0.1875+0.1406+0.1055]= 0.316$

3 0

3 years ago

Kenji is using walnuts to bake muffins and granola for his restaurant. each batch of muffins

Tasya [4]

Answer:

Step-by-step explanation:

1/2b + 2 ≤ 8

b ≤ 12

8 0

2 years ago