
Here, we want to find the diagonal of the given solid
To do this, we need the appropriate triangle
Firstly, we need the diagonal of the base
To get this, we use Pythagoras' theorem for the base
The other measures are 6 mm and 8 mm
According ro Pythagoras' ; the square of the hypotenuse equals the sum of the squares of the two other sides
Let us have the diagonal as l
Mathematically;
![\begin{gathered} l^2=6^2+8^2 \\ l^2\text{ = 36 + 64} \\ l^2\text{ =100} \\ l\text{ = }\sqrt[]{100} \\ l\text{ = 10 mm} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20l%5E2%3D6%5E2%2B8%5E2%20%5C%5C%20l%5E2%5Ctext%7B%20%3D%2036%20%2B%2064%7D%20%5C%5C%20l%5E2%5Ctext%7B%20%3D100%7D%20%5C%5C%20l%5Ctext%7B%20%3D%20%7D%5Csqrt%5B%5D%7B100%7D%20%5C%5C%20l%5Ctext%7B%20%3D%2010%20mm%7D%20%5Cend%7Bgathered%7D)
Now, to get the diagonal, we use the triangle with height 5 mm and the base being the hypotenuse we calculated above
Thus, we calculate this using the Pytthagoras' theorem as follows;
C - 3 1/12
Get a common denominator
3*3 / 4*3 + 1*4 / 3*4
Simplifies into 9/12 + 4/12
Adds to 13/12.
12 goes into 13 1 time, leaving us with 1 1/12
Add the 1 to the 2 full cups that already existed in the original problem - 3 1/12
Answer:
x= k/a-b
Step-by-step explanation:
Move all terms to the left side and set equal to zero as well as each factor.
Hope this helps.
The present of 4 out of 30 is 13.33%
The present of 1 out of 30 is 3.33%
The present of 25 out of 30 is 83.33%
<u>Step-by-step explanation:</u>
- The percentage is calculated by dividing the required number with the full quantity and multiplied by 100.
First sum :

Second sum :

Third sum:
