Here’s what I’ve done.
I’m not too sure what was meant by expanding?
What I’ve found is what power you need to get the number that’s being logged.
The last question uses a, because the question uses x.
The working I’ve done should be self-explanatory.
We know that the shortest leg of the largest right triangle (hypotenuse length 16) has a length of the square root of (y^2 + 16) through the pythagoras theorem. We also know that x is equal to the square root of (144 + y^2) as well. Finally, we know that 256 = (y^2 + 16) + (y^2 + 144), since we use the pythagoras theorem one last time and square each of the values we have got for the two legs of the largest right triangle. Therefore, 256 = 2y^2 + 160, 96 = 2y^2, 48 = y^2, y= sqrt48 = 4sqrt3 =

.
Answer:
121
Step-by-step explanation:
2^3x - 4 = (2^x )^3 - 4 = 125 - 4 = 121
Answer:
a
Step-by-step explanation: