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rjkz [21]
3 years ago
15

Tan(arcsin(x)) and its domain ...?

Mathematics
1 answer:
Mandarinka [93]3 years ago
6 0
- \frac{\pi}{2} < \arcsin{x} < \frac{\pi}{2} &#10;\\&#10;\\\sin(- \frac{\pi}{2}) < \sin(\arcsin{x}) < \sin(\frac{\pi}{2} )&#10;\\&#10;\\-1 < x < 1
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