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Allisa [31]
3 years ago
6

Use long or synthetic division to find the following quotients (x^3+2x^2!22x-45)÷(x+5) ​

Mathematics
1 answer:
svetoff [14.1K]3 years ago
7 0

Answer:

\boxed{\textsf{ The quotient is $\sf x^2-3x-7$ and the remainder is (-10).}}

Step-by-step explanation:

Here we will be using long division method to find the quotient . Here we need to divide (x³+2x²-22x-45) and (x+5) . So lets divide .

x+5) x³+2x²-22x-45 ( x² -3x -7

x³ + 5x²

- -

______________

- 3x²-22x -45

-3x² -15x

+ +

______________

-7x -45

-7x -35

______________

-10

<u>Quotient</u><u> </u>= x² -3x -7

<u>Remainder </u>= (-10)

<h3><u>★</u><u>Hence </u><u>the</u><u> </u><u>quotient</u><u> </u><u>is </u><u>x²</u><u> </u><u>-3x </u><u>-</u><u>7</u><u> </u><u>and </u><u>the</u><u> </u><u>remainder</u><u> </u><u>is </u><u>(</u><u>-</u><u>1</u><u>0</u><u>)</u><u> </u><u>.</u></h3>
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