Answer:
1,250,000 shrimps per m³
Explanation:
Population density refers to how dense an area is per unit area/volume, and it is calculated by dividing the number of individuals in that area (population) by the area/volume of that area. That is;
Population density = population (N)/volume
According to this question, a certain lake has a volume of about 480 m³ that harbors a 600 million of freshwater shrimp. This means that;
Population density of the lake = population of shrimps ÷ volume of lake
Population density = 600,000,000 ÷ 480
Population density = 1,250,000 shrimps per m³
This would be an example of overproduction. The frog lays thousands of eggs, which is more than it needs, or would need in perfect conditions.
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