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polet [3.4K]
2 years ago
6

Val is in a race that has a 2 10-mile swim and a 26 10-mile run. How far does Val

Mathematics
1 answer:
Yuri [45]2 years ago
7 0

Step-by-step explanation:

bdhdhjndnfdndnnskdkdkskdkdkd

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On a coordinate plane, triangle B C D has points (negative 4, 1), (negative 2, 1), (negative 4, 3). Triangle B prime C prime D p
tatyana61 [14]

9514 1404 393

Answer:

  90° CCW

Step-by-step explanation:

The transformation from B to B' is ...

  B(-4, 1) ⇒ B'(-1, -4)

  (x, y) ⇒ (-y, x) . . . . . matches the transformation for 90° CCW

8 0
2 years ago
Pixel goes shopping with one hundred dollars and ends up buying three different types of items: A, B, and C. The unit price of A
mixas84 [53]

Answer:

  • A - 16, B - 79, C - 5

Step-by-step explanation:

<u>Given</u>

  • A costs 5$
  • B costs  $0.25
  • C costs $0.05
  • A + B + C = 100
  • 5A + 0.25B + 0.05C = 100 ⇒ 100A + 5B + C = 2000

<u>Subtract the first equation from the second:</u>

  • 99A + 4B = 1900

<u>We have a restriction in numbers:</u>

  • 0 < A, B, C < 100

<u>Since 4B can be max 400, we get 99A > 1500  and 99A < 1900 so:</u>

  • A > 1500/99 > 15

and

  • A < 1900/99 < 19

A can be 16 or 18 as it should be even number to get B the whole number.

<u>If A = 16:</u>

  • 99*16 + 4B = 1900
  • 4B = 1900 - 1584
  • 4B = 316
  • B = 316/4 = 79

<u>If A = 18:</u>

  • 99*18 + 4B = 1900
  • 4B = 1900 - 1782
  • 4B = 118
  • B = 118/4 = 29.5, discarded as decimal

<u>So we get:</u>

  • A = 16, B = 79 and C = 100 - (16 + 79) = 5

<u>Let's proof the numbers:</u>

  • 16*5 + 79*0.25 + 5*0.05 = 100, confirmed

5 0
2 years ago
WILL MARK BRAINLIEST ASAPPPP
irinina [24]
Answer: 49.5 round up to 50

Explanation: add the area of a rectangle plus the area of a triangle
5 0
2 years ago
I need help on the following questions please wait for me to upload them. It keeps deleting my file help
Hitman42 [59]
Going down the list.

3.) 5 gal.
4.)40,000 mL
5.)8 pt
6.)0.3 kL
7.)16.5 qt, 66 pt
8.)0.29 daL
9.)64 fl oz
10.)777,000 cL (looked like 7.7)
11.)1.5 pt, 2.9 (3) c.
8 0
2 years ago
The total mass of the Sun is about 2×10^30 kg, of which about 76 % was hydrogen when the Sun formed. However, only about 12 % of
nignag [31]

Answer:

A. 1.8 ×10^{30} Kg

B i. 3.0 × 10^{17} seconds

  ii. 9.6 × 10^{9} years

C. After 9.2 × 10^{9} (9.2 billion) years

Step-by-step explanation:

Given that the mass of the Sun = 2× 10^{30} Kg.

Mass of hydrogen when Sun was formed = 76% of 2× 10^{30} Kg

                            = \frac{76}{100}  ×2× 10^{30} Kg

                           = 1.52 × 10^{30} Kg

Mass of hydrogen available for fusion = 12% of 1.52 × 10^{30} Kg

                           = \frac{12}{100} × 1.52 × 10^{30} Kg

                           = 1.824 ×10^{30} Kg

A. Total mass of hydrogen available for fusion over the lifetime of the sun is 1.8 ×10^{30} Kg.

B. Given that the Sun fuses 6 × 10^{11} Kg of hydrogen each second.

i. The Sun's initial hydrogen would last;

                                     \frac{1.8*10^{30} }{6*10^{11} }

                                 = 3.04 × 10^{17} seconds

The Sun's hydrogen would last 3.0 × 10^{17} seconds

ii. Since there are 31536000 seconds in a year, then;

The Sun's initial hydrogen would last;

                                     \frac{3.04*10^{17} }{31536000}

                                 = 9.640 × 10^{9} years

The Sun's hydrogen would last 9.6 × 10^{9} years.

C. Given that our solar system is now about 4.6 × 10^{9} years, then;

                               \frac{9.6*10^{9} }{4.6*10^{9} }

                             = 2.09

So that;   2 × 4.6 × 10^{9} = 9.2 × 10^{9} years

Therefore, we need to worry about the Sun running out of hydrogen for fusion after 9.2 × 10^{9} years.

6 0
3 years ago
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