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BlackZzzverrR [31]
3 years ago
15

10

Mathematics
1 answer:
Naily [24]3 years ago
8 0

Answer:

295275392

2864263924729

8639253925339

9739373027303

9283634828

293682537474(483

926338286328+

92632926282727

93739363825282

92362836273

9263935392628

9273926382639

926329638392

92639236926

92632863922

9273936

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A. What is an equation of the line with slope -1/2 and y-intercept 2??
Brrunno [24]

Answer:

y = -(1/2)x + 2

Step-by-step explanation:

6 0
3 years ago
Josh has some nickels. He says they are worth exactly 33 cents. Can you tell if Josh is correct or not?
Katyanochek1 [597]

Answer: Josh is incorrect because nickels are worth 5 cents each and 33 can not be divided by 5 exactly.

8 0
3 years ago
The increasing annual cost (including tuition, room, board, books, and fees) to attend college has been widely discussed (Time).
NeX [460]

Answer:

(a) PRIVATE COLLEGES

Sample mean is $42.5 thousand

Sample standard deviation is $6.65 thousand

PUBLIC COLLEGES

Sample mean is $22.3 thousand

Sample standard deviation is $4.34 thousand

(b) Point estimate is $20.2 thousand. The mean annual cost to attend private colleges ($42.5 thousand) is more than the mean annual cost to attend public colleges ($22.3 thousand)

(c) 95% confidence interval of the difference between the mean annual cost of attending private and public colleges is $19.2 thousand to $21.2 thousand

Step-by-step explanation:

(a) PRIVATE COLLEGES

Sample mean = Total cost ÷ number of colleges = (51.8+42.2+45+34.3+44+29.6+46.8+36.8+51.5+43) ÷ 10 = 425 ÷ 10 = $42.5 thousand

Sample standard deviation = sqrt[summation (cost - sample mean)^2 ÷ number of colleges] = sqrt([(51.8-42.5)^2 + (42.2-42.5)^2 + (45-42.5)^2 + (34.3-42.5)^2 + (44-42.5)^2 + (29.6-42.5)^2 + (36.8-42.5)^2 + (51.5-42.5)^2 + (43-42.5)^2] ÷ 10) = sqrt (44.24) = $6.65 thousand

PUBLIC COLLEGES

Sample mean = (20.3+22+28.2+15.6+24.1+28.5+22.8+25.8+18.5+25.6+14.4+21.8) ÷ 12 = 267.6 ÷ 12 = $22.3 thousand

Sample standard deviation = sqrt([(20.3-22.3)^2 + (22-22.3)^2 + (28.2-22.3)^2 + (15.6-22.3)^2 + (24.1-22.3)^2 + (28.5-22.3)^2 + (22.8-22.3)^2 + (25.8-22.3)^2 + (18.5-22.3)^2 + (25.6-22.3)^2 + (14.4-22.3)^2 + (21.8-22.3)^2] ÷ 12) = sqrt (18.83) = $4.34 thousand

(b) Point estimate = mean annual cost of attending private colleges - mean annual cost of attending public colleges = $42.5 thousand - $22.3 thousand = $20.2 thousand.

This implies the the mean annual cost of attending private colleges is greater than the mean annual cost of attending public colleges

(c) Confidence Interval = Mean + or - Margin of error (E)

E = t×sd/√n

Mean = $42.5 - $22.3 = $20.2 thousand

sd = $6.65 - $4.34 = $2.31 thousand

n = 10+12 = 22

degree of freedom = 22-2 = 20

t-value corresponding to 20 degrees of freedom and 95% confidence level is 2.086

E = 2.086×$2.31/√22 = $1.0 thousand

Lower bound = Mean - E = $20.2 thousand - $1.0 thousand = $19.2 thousand

Upper bound = Mean + E = $20.2 thousand + $1.0 thousand = $21.2 thousand

95% confidence interval is $19.2 thousand to $21.2 thousand

6 0
3 years ago
Solve this ASAP 12/y equals 4/3
OLEGan [10]

Answer:

y=9

hope this helps

have a good day :)

Step-by-step explanation:

4 0
3 years ago
WORTH 80 POINTS HELP
vekshin1
Hi!

1. Your answer should be the first option. (It looks the best to me)

2. it is the last option because it's the only one that's identical to the original picture.

3. It should be the third option since there are 10cm on the top of the shape.

4. a total of 39

Hope that helps, good luck! :)
6 0
3 years ago
Read 2 more answers
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