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GenaCL600 [577]
3 years ago
6

Which algebraic expression represents 10 less than a number​

Mathematics
2 answers:
alekssr [168]3 years ago
6 0

Answer:

n-10

Step-by-step explanation:

"n" represents the number, then you put minus 10, because it's 10 less than the number.

GarryVolchara [31]3 years ago
4 0

Answer:

Step-by-step explanation:

Let the number be x

x - 10

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Can someone help me with these 4 geometry questions? Pls it’s urgent, So ASAP!!!!
blagie [28]

<u>Question 4</u>

1) \overline{BD} bisects \angle ABC, \overline{EF} \perp \overline{AB}, and \overline{EG} \perp \overline{BC} (given)

2) \angle FBE \cong \angle GBE (an angle bisector splits an angle into two congruent parts)

3) \angle BFE and \angle BGE are right angles (perpendicular lines form right angles)

4) \triangle BFE and \triangle BGE are right triangles (a triangle with a right angle is a right triangle)

5) \overline{BE} \cong \overline{BE} (reflexive property)

6) \triangle BFE \cong \triangle BGE (HA)

<u>Question 5</u>

1) \angle AXO and \angle BYO are right angles, \angle A \cong \angle B, O is the midpoint of \overline{AB} (given)

2) \triangle AXO and \triangle BYO are right triangles (a triangle with a right angle is a right triangle)

3) \overline{AO} \cong \overline{OB} (a midpoint splits a segment into two congruent parts)

4) \triangle AXO \cong \triangle BYO (HA)

5) \overline{OX} \cong  \overline{OY} (CPCTC)

<u>Question 6</u>

1) \angle B and \angle D are right angles, \overline{AC} bisects \angle BAD (given)

2) \overline{AC} \cong \overline{AC} (reflexive property)

3) \angle BAC \cong \angle CAD (an angle bisector splits an angle into two congruent parts)

4) \triangle BAC and \triangle CAD are right triangles (a triangle with a right angle is a right triangle)

5) \triangle BAC \cong \triangle DCA (HA)

6) \angle BCA \cong \angle DCA (CPCTC)

7) \overline{CA} bisects \angle ACD (if a segment splits an angle into two congruent parts, it is an angle bisector)

<u>Question 7</u>

1) \angle B and \angle C are right angles, \angle 4 \cong \angle 1 (given)

2) \triangle BAD and \triangle CAD are right triangles (definition of a right triangle)

3) \angle 1 \cong \angle 3 (vertical angles are congruent)

4) \angle 4 \cong \angle 3 (transitive property of congruence)

5) \overline{AD} \cong \overline{AD} (reflexive property)

6) \therefore \triangle BAD \cong \triangle CAD (HA theorem)

7) \angle BDA \cong \angle CDA (CPCTC)

8) \therefore \vec{DA} bisects \angle BDC (definition of bisector of an angle)

8 0
2 years ago
Write the word phrases into an algebraic expression : 4 less than 5 times a number "p"
shusha [124]
Answer: 5p - 4

5 times ‘p’ = 5p
4 less than ‘p’ = p - 4

Therefore,
=> 5p - 4
4 0
2 years ago
Jacks family bought five concert tickets for $250 what was the price per ticket?
Mashcka [7]

answer : 0.02

$250 ÷ 5 = 0.02

5 0
2 years ago
Read 2 more answers
I desperately need help !
Lorico [155]

Answer:

t = 9.57

Step-by-step explanation:

We can use trig functions to solve for the t

Recall the 3 main trig ratios

Sin = opposite / hypotenuse

Cos = adjacent / hypotenuse

Tan = opposite / adjacent.

( note hypotenuse = longest side , opposite = side opposite of angle and adjacent = other side )

We are given an angle as well as its opposite side length ( which has a measure of 18 ) and we need to find its adjacent "t"

When dealing with the opposite and adjacent we use trig ratio tan.

Tan = opp / adj

angle measure = 62 , opposite side length = 18 and adjacent = t

Tan(62) = 18/t

we now solve for t

Tan(62) = 18/t

multiply both sides by t

Tan(62)t = 18

divide both sides by tan(62)

t = 18/tan(62)

t = 9.57

And we are done!

3 0
2 years ago
Read 2 more answers
Los lados de un triángulo rectángulo tienen por medida tres números enteros consecutivos. Calcula los lados del triángulo.
elixir [45]

Answer:

Los lados del triángulo rectángulo miden 3, 4 y 5, respectivamente.

Step-by-step explanation:

Un triángulo rectángulo puede ser descrito mediante el teorema de Pitágoras, para el caso de tres lados representando tres números enteros consecutivos, tenemos que:

(n+2)^{2} = n^{2} + (n+1)^{2} (1)

Donde n es un número natural.

A continuación, expandimos la expresión y resolvemos:

n^{2}+4\cdot n +4 = n^{2} + n^{2} +2\cdot n + 1

n^{2}-2\cdot n -3 = 0

(n -3) \cdot (n+1) = 0

La única solución factible es n = 3. En consecuencia, los lados del triángulo rectángulo miden 3, 4 y 5, respectivamente.

4 0
3 years ago
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