Answer:
I believe it might be 30 or 1.2
Step-by-step explanation:
It would've been 6/30 but since is it says it's a whole number you would have to add all the numbers together to get how many marbles you have in all.
I hope this is right, if it's not I'm sorry!
Answer:
x = 50
Step-by-step explanation:
Since this is a right triangle we can use special triangles
The angle next to the x is 60 degrees since it is a 30 60 90 triangle
The side opposite the 30 degree angle is the shorter side
The hypotenuse - 2 * shorter leg
100 = 2 * x
x = 50
Answer:144
Step-by-step explanation: a coin has 2 possibilities so 2 coins have 2x2 = 4 possibilities. A normal six-sided dice has 6x6 = 36 possibilities. 4 x 36 = 144 (this might be wrong)
Given that the first term of the sequence is –1.5, the next term of the sequence would be 3
<h3>How to determine the next term?</h3>
The recursive function is given as:
f(n + 1) = -2f(n)
Substitute 1 for n
f(1 + 1) = -2f(1)
Evaluate
f(2) = -2f(1)
Given that the first term is -1.5, the equation becomes
f(2) = -2 * -1.5
Evaluate
f(2) = 3
Hence, the next term of the sequence is 3
Read more about sequence at:
brainly.com/question/6561461
#SPJ4
Answer:
Step-by-step explanation:
Let the length of one side of the square base be x
Let the height of the box by y
Volume of the box V = x²y
Since the box is opened at the top, the total surface area S = x² + 2xy + 2xy
S = x² + 4xy
Given
S = 7500sq in.
Substitute into the formula for calculating the total surface area
7500 = x² + 4xy
Make y the subject of the formula;
7500 - x² = 4xy
y = (7500-x²)/4x
Since V = x²y
V = x² (7500-x²)/4x
V = x(7500-x²)/4
V = 1/4(7500x-x³)
For us to maximize the volume, then dV/dx = 0
dV/dx = 1/4(7500-3x²)
1/4(7500-3x²) = 0
(7500-3x²) = 0
7500 = 3x²
x² = 7500/3
x² = 2500
x = √2500
x = 50in
Since y = (7500-x²)/4x
y = 7500-2500/4(50)
y = 5000/200
y = 25in
Hence the dimensions of the box that will maximize its volume is 50in by 50in by 25in.
The Volume of the box V = 50²*25
V = 2500*25
V= 62,500in³
Hence the maximum volume is 62,500in³