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3 years ago

Please hurry I’m timed geometry

Mathematics

1 answer:

xeze [42]3 years ago

3 0

Answer is c because is asking for where the point A’ b’ c’ D’ are located and point A’ is located on (-5,-5) on the graph

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A particle moves in a straight line so that its velocity at time

riadik2000 [5.3K]

Answer:

s(2) = 7.75

Step-by-step explanation:

given the velocity v(t) = t^3

we can find the position s(t) by simply integrating v(t) and using the boundary conditions s(1)=2

$s(t) = \int {v(t)} \, dt\\ s(t) = \int {t^3} \, dt\\s(t) = \dfrac{t^4}{4}+c$

we know throught s(1) = 2, that at t=1, s =2. we can use this to find the value of the constant c.

$s(1) = \dfrac{1^4}{4}+c\\4 = \dfrac{1^4}{4}+c\\c = 4-\dfrac{1}{4}\\c = \dfrac{15}{4} = 3.75$

Now we can use this value of t to formulate the position function s(t):

$s(t) = \dfrac{t^4}{4}+\dfrac{15}{4}\\$

this is the position at time t.

to find the position at t=2

$s(2) = \dfrac{2^4}{4}+\dfrac{15}{4}\\$

$s(2) = \dfrac{31}{4} = 7.75$

the position of the particle at time, t =2 is s(2) = 7.75

3 0

3 years ago

Subtract 4/9 and 1/5 in the simplest form

Reptile [31]

Answer:

4/9 or 0.4

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Try It Yourself Find 0.2% of 126, rounding your answer to 3 significant figures if needed

sweet [91]

Answer:

0.252

Step-by-step explanation:

0.2 ×126

100

0.252

4 0

3 years ago

Will give brainliest

Alexandra [31]

Answer:

p and q are parallel to each other and l, m, and n are all parallel

Step-by-step explanation:

because it tells us they make right angles we know all the lines are going straight therefor they will not intersect with each other

6 0

3 years ago

Calculate the velocity of a moving train with a mass 10,000kg and 150,000J of energy.

Viefleur [7K]

Kinetic energy possessed by moving train is $E_k = 150000J$ .

And mass $m = 10000kg$ .

The formula for kinetic energy is $E_k = \frac{m\times v^2}{2}$ .

Solve for velocity:

$E_k = \frac{m\times v^2}{2}\implies 2E_k = m\times v^2$

$v^2=\frac{2E_k}{m}\implies \underline{v = \sqrt{\frac{2E_k}{m}}}$

Now put in the data:

$v = \sqrt{\frac{2\times150000J}{10000kg}}\approx5.48\frac{m}{s}$

5 0

3 years ago