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CaHeK987 [17]
3 years ago
9

you have 200 grams of a radioactive kind of iodine how much will ne left after 120 days if its half life is 60 days?

Mathematics
1 answer:
ElenaW [278]3 years ago
4 0

By definition, the half life is a quantity is the time it takes to lose half of that quantity.

So, if the half life is 60 days, it means that after 60 days you have lost half the initial amount, i.e. you're left with 100 grams.

After another 60 days, you've lost, again, half of that amount, so you're left with 50 grams.

In other words, every time a half life period passes, you're left with half the quantity you had at the beginning of that period.

So, after two half-life periods (i.e. 120 days), you'll have half of the half of the initial quantity, i.e. one quarter.

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Answer:

x=\frac{13}{2}, y=\frac{51}{4}

Step-by-step explanation:

We\ are\ given,\\3x-2y=-6\\5x-2y=7\\Considering\ this\ system\ of\ equations,\\Let\ 3x-2y=-6\ be\ E_1\\Let\ 5x-2y=7\ be\ E_2,\\Hence,\\Multiplying\ E2\ with\ -1, we\ get:\\3x-2y=-6\\-1(5x-2y)=7*-1\\Hence,\\3x-2y=-6\\-5x+2y=-7\\Now,\\Lets\ add\ E_1\ and\ E_2\ together\\Hence,\\(3x-2y)+(-5x+2y)=(-6)+(-7)\\Hence,\\3x-2y-5x+2y=-13\\Arranging\ And\ Adding\ Like\ terms,\ we\ have:\\3x-5x-2y+2y=-13\\Hence,\\-2x+0y=-13\\-2x=-13\\x=\frac{-13}{-2}=\frac{13}{2}

Now,\ we\ can\ substitute\ x=\frac{13}{2}\ in\ E_1\ or\ E_2,\\But,\\Here,\ we'll\ substitute\ it\ in\ E1,\\Hence,\\Substituting\ x=\frac{13}{2}\ in\ E1,\ we\ have:\\3*\frac{13}{2}-2y=-6\\\frac{39}{2}-2y=-6\\-2y=-6- \frac{39}{2}\\-2y=\frac{-12-39}{2}\\-2y=\frac{-51}{2}\\y=\frac{-51}{2*-2}=\frac{51}{4}\\Hence,\\x=\frac{13}{2}, y=\frac{51}{4}

4 0
3 years ago
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Answer:

469

Step-by-step explanation:

  1. Difference = subtraction
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I hope this helps!

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Not really because there only three but u might get red thought
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Since c is located slightly less than -1, and -1+2 = 1; then adding 2 to c would make it slightly less than 1.

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2 years ago
4. a) In a sale, a car costing $ 9500 Średuced by<br>30%<br>what's the sale Price?​
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Answer:

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