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goblinko [34]
3 years ago
13

Will give brainliest!!

Mathematics
2 answers:
kirill115 [55]3 years ago
8 0
It’s the one that is marked as (3,3)
blagie [28]3 years ago
4 0

Answer:

Second one

Step-by-step explanation:

The first line has a negative slope, that is means that it decreases (we have to watch the graph from left to right)

6 is the point where it Intercepts the y axis

For now we can say that only the second and the fourth graph can be correct

The second line has a positive slope, so it increases (we have to watch the graph from left to right)

-3 is the point where it intercepts the y axis

the second graph shows what we want

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What can you tell about the men’s of each distribution? Plsss help I’m stuck I do not want to get a bad grade on this
Vitek1552 [10]

Answer:

c i belive

Step-by-step explanation:

bec why not dude it seems to be self explanatory through the explanation

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3 0
4 years ago
Pls answer ASAP this is timed and don’t put a link
Serjik [45]

Answer:

C: mean 6.5 median 6

Step-by-step explanation:

median you find middle number in sorted numbers lined up. mean is all numbers added up and divided by how many there are

8 0
3 years ago
Is each line parallel, perpendicular, or neither parallel nor perpendicular to a line whose slope is −6?
ikadub [295]
Line M with slope 6 is neither, line n with slope -6 is parallel because only lines with same slope are parallel, line p with slope 1/6 is neither. and line q with slope -1/6 is perpendicular because only the reciprocal of a slope is perpendicular, so reciprocal of 6= 1/6 reciprocal of -6=-1/6 reciprocal of 2= 1/2
8 0
3 years ago
Read 2 more answers
How to know if a function is periodic without graphing it ?
zhenek [66]
A function f(t) is periodic if there is some constant k such that f(t+k)=f(k) for all t in the domain of f(t). Then k is the "period" of f(t).

Example:

If f(x)=\sin x, then we have \sin(x+2\pi)=\sin x\cos2\pi+\cos x\sin2\pi=\sin x, and so \sin x is periodic with period 2\pi.

It gets a bit more complicated for a function like yours. We're looking for k such that

\pi\sin\left(\dfrac\pi2(t+k)\right)+1.8\cos\left(\dfrac{7\pi}5(t+k)\right)=\pi\sin\dfrac{\pi t}2+1.8\cos\dfrac{7\pi t}5

Expanding on the left, you have

\pi\sin\dfrac{\pi t}2\cos\dfrac{k\pi}2+\pi\cos\dfrac{\pi t}2\sin\dfrac{k\pi}2

and

1.8\cos\dfrac{7\pi t}5\cos\dfrac{7k\pi}5-1.8\sin\dfrac{7\pi t}5\sin\dfrac{7k\pi}5

It follows that the following must be satisfied:

\begin{cases}\cos\dfrac{k\pi}2=1\\\\\sin\dfrac{k\pi}2=0\\\\\cos\dfrac{7k\pi}5=1\\\\\sin\dfrac{7k\pi}5=0\end{cases}

The first two equations are satisfied whenever k\in\{0,\pm4,\pm8,\ldots\}, or more generally, when k=4n and n\in\mathbb Z (i.e. any multiple of 4).

The second two are satisfied whenever k\in\left\{0,\pm\dfrac{10}7,\pm\dfrac{20}7,\ldots\right\}, and more generally when k=\dfrac{10n}7 with n\in\mathbb Z (any multiple of 10/7).

It then follows that all four equations will be satisfied whenever the two sets above intersect. This happens when k is any common multiple of 4 and 10/7. The least positive one would be 20, which means the period for your function is 20.

Let's verify:

\sin\left(\dfrac\pi2(t+20)\right)=\sin\dfrac{\pi t}2\underbrace{\cos10\pi}_1+\cos\dfrac{\pi t}2\underbrace{\sin10\pi}_0=\sin\dfrac{\pi t}2

\cos\left(\dfrac{7\pi}5(t+20)\right)=\cos\dfrac{7\pi t}5\underbrace{\cos28\pi}_1-\sin\dfrac{7\pi t}5\underbrace{\sin28\pi}_0=\cos\dfrac{7\pi t}5

More generally, it can be shown that

f(t)=\displaystyle\sum_{i=1}^n(a_i\sin(b_it)+c_i\cos(d_it))

is periodic with period \mbox{lcm}(b_1,\ldots,b_n,d_1,\ldots,d_n).
4 0
3 years ago
-22 + (-16)<br> Hhhhhhhhhhhhhhhhhhhhhh
Ad libitum [116K]

Answer:

-22 + (-16)= -38

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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