In low light no plants grow. With no plants no animals can eat so less animals remain or stay there. With less animals less animals respire and breathe out CO2.
I think your answer is a hot summer. during this phase, there would be rapid growth in vegetation leading to increased population in rabbits and other rodents...
If a cell membrane became impermeable, instead of selectively permeable, the cell would not remain alive, though certain organisms would be able to stay alive longer than others. This is because the cell membrane allows essential molecules and substances such as oxygen into the cell, while allowing harmful substances, like waste, out of the cell.
:)
Answer:
Function will be disrupted by adding the urea and regained by removing the urea.
Explanation:
The protein is one of the important biomolecule made of the polymers of the alpha amino acids that are linked together by peptide bonds. The protein works at their specific pH.
Denaturants disrupt the 3 dimensional structure of protein that affect their normal functioning. In the given experiment, the urea acts as denaturant and disrupt the protein structure. The removal of urea will reverse the denaturant condition and protein gain its function.
Thus, the correct answer is option (a).
Answer:
the respective means of growth within an organism varies from organism to organism. For instance, multicellular organisms grow via a process of cellular division known as mitosis, while others (being unicellular) grow or reproduce colonially-speaking via a process called binary fission.
Explanation:
Hope this helps!!
