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3 years ago

I need help on science if this is true or false

Chemistry

2 answers:

zheka24 [161]3 years ago

5 0

Answer:

I am pretty sure it is False

Explanation:

sukhopar [10]3 years ago

4 0

Answer:

The second statement is false

Explanation:

Diffusion will typically occur until concentration gradients are the same both outside and inside of the cell. In order for the concentration to increase further inside of the cell requires a different transportation method, such as the use of a channel protein.

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The answer is caves.. i think

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John has to hit a bottle with a ball to win a prize. He throws a 0.4 kg ball with a velocity of 18 m/s. It hits a 0.2 kg bottle,

enot [183]

One can solve the problem by using the law of conservation of momentum. The total momentum prior to the collision must be equivalent to the total momentum after the collision, so we have:

m1v1 + m2v2 = m1v1 + m2v2

Here, m1 is 0.4 Kg that is the mass of the ball, u1 is 18 m/s that is the initial velocity of the ball, m2 is 0.2 Kg that is the mass of the bottle, and u2 is 0 that is the initial velocity of the bottle.

v1 is the final velocity of the ball, which is to be determined, and v2 is 25 m/s that is the final velocity of the bottle.

Substituting and rearranging the equation, one can find the final velocity of the ball:

v1 = m1u1 - m2v2 / m1 = (0.4 kg) (18 m/s) - (0.2 Kg) (25 m/s) / 0.4 Kg = 5.5 m/s.

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3 years ago

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How many moles and numbers of ions of each type are present in the following aqueous solution? 63.1 mL of 1.85 M magnesium chlor

Alexxandr [17]

Answer:

We have 0.117 moles Mg^2+ and 0.234 moles Cl-

The number of Mg^2+ ions = 7.04 *10^22 ions

The number of Cl- ions = 1.4*10^23 ions

Explanation:

Step 1: Data given

Volume of magnesium chloride = 63.1 mL

Concentration of solution = 1.85 M

Step 2: Calculate moles MgCl2

Moles MgCl2 = concentration * volume

Moles MgCl2 = 1.85 M * 0.0631 L

Moles MgCl2 = 0.117 moles

Step 3: Calculate moles of ions

MgCl2 → Mg^2+ + 2Cl-

For 1 mol MgCl2 we have 1 mol Mg^2+ and 2 moles Cl-

For 0.117 moles MgCl2 we have 0.117 moles Mg^2+ and 2*0.117 = 0.234 moles Cl-

The number of Mg^2+ ions = 0.117 * 6.022 *10^23 = 7.04 *10^22 ions

The number of Cl- ions = 1.4*10^23 ions

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4 years ago

Give the complete ionic equation for the reaction (if any) that occurs when aqueous solutions of lithium sulfide and copper (II)

Aloiza [94]

Answer:

$2Li^+_{(aq)}+S^{2-}_{(aq)}+Cu^{2+}_{(aq)}+2NO_3^{-}_{(aq)}\rightarrow CuS_{(s)}+2Li^+_{(aq)}+2NO_3^{-}_{(aq)}$

Explanation:

Complete ionic equation : In complete ionic equation, all the substance that are strong electrolyte and present in an aqueous are represented in the form of ions.

The balanced molecular equation will be,

$Li_2S_{(aq)}+Cu(NO_3)_2_{(aq)}\rightarrow CuS_{(s)}+2LiNO_3_{(aq)}$

The complete ionic equation in separated aqueous solution will be,

$2Li^+_{(aq)}+S^{2-}_{(aq)}+Cu^{2+}_{(aq)}+2NO_3^{-}_{(aq)}\rightarrow CuS_{(s)}+2Li^+_{(aq)}+2NO_3^{-}_{(aq)}$

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