B. Extrusion
<u>Explanation:</u>
Extrusion process is not involved in the process of formation of sedimentary rocks. These rocks are formed by following processes -
1) weathering of preexisting rocks
2) transport of the weathering products
3) deposition of the material
4) compaction
5) cementation of the sediment to form a rock
At the point when rocks are at or close to the outside of the earth they are presented to the procedures of weathering. Sediments are deposited layer upon layer. The layers are kept evenly. As sedimentation proceeds, the prior stored residue are weighed down with an expanding overburden. They are compacted, diminishing the accessible pore space and removing a significant part of the pore-water.
Answer is: <span>a. c6h14 and c10h20.
This pair will </span>most likely form a homogeneous solution because they are both nonpolar substances and "li<span>ke dissolves like".
Other pairs will not form homogeneous solution because nonpolar substances have low solubility in polar or ionic substances (for example LiBr is ionic and C</span>₅H₁₂ is nonpolar).
<span>From Graham's law of diffusion.
Rate of diffusion of Neon/Rate of diffusion of Bromine =âš(Molar mass of bromine gas/Molar mass of Neon) Molar mass of bromine gas =79.904 and Molar mass of Neon = 20.17. So we have. âš(79.904/20.17) from the right hand side of the equation. Hence it follows that.
Rate of diffusion of Neon/Rate of diffusion of Bromine = âš3.96 = 1.98. Hence it follows that Rate of Diffusion of Neon is 1.98 or (2 times, to1d.p) the rate of diffusion of Bromine.</span>
The classical bonding model which best explains the bonding in the compound NaH₂PO₄ is Hydrogen bonding.
<h3>What is Classical bonding model ?</h3>
By classical, we mean models that do not take into account the quantum behavior of small particles, notably the electron.
These models generally assume that electrons and ions behave as point charges which attract and repel according to the laws of electrostatics.
Sodium dihydrogen phosphate (NaH₂PO₄) is monoclinic, In which, the four independent hydrogen atoms were located on a difference map; they are involved in four O … O Hydrogen-bonds of length 2.654 (2), 2.589 (2), 2.559 (2), and 2.500 (2) Å.
The short contact (2.500 Å), which is not astride any symmetry element, is of the type O-H … O (asymmetrical).
The distorted coordination polyhedra of the sodium atoms are discussed in the light of recent theories on electrostatic balance.
Hence, the classical bonding model which best explains the bonding in the compound NaH₂PO₄ is Hydrogen bonding.
Laern more about Bonding model here ;
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The most common method astronomers use to determine the composition of stars, planets, and other objects is spectroscopy. Today, this process uses instruments with a grating that spreads out the light from an object by wavelength. This spread-out light is called a spectrum.
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