<span>Common Factors of 32 and 36
factors of 32 = 1, 2, 4, 8, 16 and 32
factors of 36 = 1, 2, 3, 4, 6, 9, 18, 36
So the common factors of 32 and 36 are 1, 2 and 4.
The greatest common factor is 4</span>
29 dimes because if you would divide the amount of pennies by 10, you'd get 29.
Let's call a child's ticket
and an adult's ticket
. From this, we can say:
,
since 116 tickets are sold in total.
Now, we are going to need to find another equation (the problem asks us to solve a systems of equations). This time, we are not going to base the equation on ticket quantity, but rather ticket price. We know that an adult's ticket is $17,000, and a child's ticket is thus
.
Given these values, we can say:
,
since each adult ticket
costs 17,000 and each child's ticket
costs 12,750, and these costs sum to 1,653,250.
Now, we have two equations:


Let's solve:


- Find
on its own, which will allow us to substitute it into the first equation

- Substitute in
for 

- Apply the Distributive Property


- Subtract 1972000 from both sides of the equation and multiply both sides by -1

We have now found that 75 child's tickets were sold. Thus,
,
41 adult tickets were sold as well.
In sum, 41 adult tickets were sold along with 75 child tickets.
6a+16
Explanation:
If there's just a variable, there's an understood 1 in front of it. So what that really says is:
7a-1a+16
So, you combine the a's. 7a minus 1a is 6a. Same as 7-1,but you have a variable stuck on the end of it.
6a+16
:^)