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OleMash [197]
3 years ago
6

Tyler and frazer weigh a total of 23kg.tyler is 7kg heavier than frazer.How much do they each weigh

Mathematics
2 answers:
alekssr [168]3 years ago
4 0

Answer:

frazer = 8kg

tyler = 15kg

Step-by-step explanation:

let x be the weight of frazer

2x + 7kg = 23kg

2x = 16

x = 8

tyler's weight = 8+7 = 15

kifflom [539]3 years ago
3 0

Step-by-step explanation:

if tyler is 7kg

frazer is 23-7kg

so he is 16kg

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4 0
3 years ago
What does the remainder theorem conclude given that f(x)x+3 has a remainder of 11?
Slav-nsk [51]

By the remainder theorem of polynomial division, the complete equation is f(-3) = 11

<h3>How to complete the blanks?</h3>

The equation is given as:

f(x)/x + 3

Set the divisor to 0

x + 3 = 0

Solve for x

x = -3

Given that the quotient has a remainder of 11.

It means that:

f(-3) = 11

Hence, the complete equation is f(-3) = 11

Read more about remainder theorem at:

brainly.com/question/13328536

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5 0
3 years ago
Can you help me please with this question
GREYUIT [131]

Answer:

132

Step-by-step explanation:

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6 0
3 years ago
Find the average rate of change over the given interval f(x)=3^x,[1,4]
nexus9112 [7]

Answer:

26

Step-by-step explanation:

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7 0
3 years ago
Does a triangle with side lengths 7, StartRoot 80 EndRoot, and StartRoot 31 EndRoot from a right triangle?
AlladinOne [14]

Answer and Step-by-step explanation:

The sides we have are 7, \sqrt{80} , and \sqrt{31} .

The square root of 80 is less than 9 but greater than 8 (because 8^2 is 64, 9^2 is 81, and 80 is in between those two values), and the square root of 31 is definitely less than the square root of 80.

So, \sqrt{80} is the longest side.

1) The square of \sqrt{80} is: (\sqrt{80} )^2=80

2) The sum of the squares of the two shorter sides is:

7^2+(\sqrt{31} )^2=49+31=80

3) Since the square of the longest side is equal to the sum of the squares of the two shorter sides, by the Pythagorean Theorem, the triangle is a right triangles.

Hope this helps!

4 0
3 years ago
Read 2 more answers
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