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Arlecino [84]
3 years ago
6

WILL MARK BRAINLIEST IF RIGHT !

Mathematics
2 answers:
dimulka [17.4K]3 years ago
7 0
It depends on how many miles they plan to drive as to which would be the better deal. Is there more context to the question?
valina [46]3 years ago
3 0

Answer:

Here you go

Step-by-step explanation:

You might be interested in
Please help I'm lost.
vova2212 [387]

Part 1: Answer:

(x+1)(x+1)(x-6) = x^3 - 4x^2 - 11x - 6

Step-by-step explanation:

To make r a root, include (x-r) as a factor. (-1+1)(-1+1)(-1-6) is zero even though (-1-6) isn't.

(6+1)(6+1)(6-6) is zero.


Part 2 Answer:

Standard form: y = -x^4 + 12

Degree 4

left end goes down, right end goes down.

Step by step: apply the definitions of standard form, polynomial degree, and "end behavior". In other words, read the textbook.


Part 3: Answer: x = 3, x = 8

Step by step:

x^2-11x = -24

x^2-11x+24 = 0

(x-3)(x-8) = 0

x = 3 or x = 8


Part 4a Answer:

quotient 2x^2 + x - 3

remainder 1


Step by step:

2x^2 + x - 3

___________________

x-4 ) 2x^3 - 7x^2 - 7x + 13

2x^3 - 8x^2

__________

0 + x^2 - 7x + 13

x^2 - 4x

____________

0 - 3x + 13

- 3x + 12

______

1


Part 4b answer:

quotient 2x^2 - 6x + 2

remainder -20


Step by step: you have to know exactly what you are doing. Refer to textbook or Wikipedia.


dividend 2x^3 +14x^2 - 58x

divisor x+10

leading coefficient of divisor must be 1

write coefficients of dividend at top

write coefficients of dividend at left


| 2 14 -58 0

-10 | -20 60 -20

___________

| 2 -6 2 -20

Coefficients of quotient are 2 -6 2

Remainder is -20

quotient = 2x^2 - 6x + 2



7 0
3 years ago
Can someone please help with #16
ollegr [7]

Answer:

∠ WZX = 50°

XW is not an altitude.

Step-by-step explanation:

16. See the attached figure.

XW is the angle bisector of ∠ YXZ, hence, ∠ WXY = ∠ WXZ

Now, given that ∠ YXZ = 8x + 34 and ∠ WXY = 10x - 13

Hence, ∠ YXZ = 2 ∠ WXY

⇒ 8x + 34 = 2(10x - 13)

⇒ 8x + 34 = 20x - 26

⇒ 12x = 60

⇒ x = 5.

Hence, ∠ XZY = ∠ WZX = 10x = 50° (Answer)

Now, ∠ WXZ = ∠ WXY = 10x - 13 = 37°

Hence, from Δ WXZ,

∠ WZX + ∠ WXZ + ∠ XWZ = 180°

⇒ 50° + 37° + ∠ XWZ = 180°

⇒ ∠ XWZ = 93° ≠ 90°

Hence, XW is not an altitude. (Answer)

6 0
3 years ago
Question 1. Enter the ratio equivalent to sin(B)
Deffense [45]

Answer:

The three questions about the given triangle has been answered below.

Step-by-step explanation:

We are given a right angled triangle whose sides are of length 20, 21 and 29.

<u>(1)</u> sin(B) = \frac{side opposite to B}{hypotenuse}

              = \frac{21}{29}

              = 0.72

<u>(2)</u> sin(A) = \frac{20}{29}

     sin(A)  = 0.689

     ∠CAB = sin^{-1}(0.689)

     ∠CAB = 43.551°

<u>(3)</u> We suppose that cosA < sinA and we haveto find which all angles will satisfy this condition.For this the angle A should be greater than 45°.

From the given options the angles that satisfy this are 55 , 66 and 75.

45 is not included as then sinA = cosA and that condition is not there.

8 0
3 years ago
Write 31 5 as a mixed number.
vaieri [72.5K]

Answer:

6 1/5

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Find the linear equation in slope intercept form that passes through the points (5,3) and (2,-1)
padilas [110]

\bf (\stackrel{x_1}{5}~,~\stackrel{y_1}{3})\qquad  (\stackrel{x_2}{2}~,~\stackrel{y_2}{-1}) \\\\\\ slope =  m\implies  \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-1-3}{2-5}\implies \cfrac{-4}{-3}\implies \cfrac{4}{3} \\\\\\ \stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-3=\cfrac{4}{3}(x-5)\implies y-3=\cfrac{4}{3}x-\cfrac{20}{3} \\\\\\ y=\cfrac{4}{3}x-\cfrac{20}{3}+3\implies y=\cfrac{4}{3}x-\cfrac{11}{3}

8 0
3 years ago
Read 2 more answers
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