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mart [117]
3 years ago
12

A rectangular piece of wood has a perimeter of 18 meters. If we multiply both its length and its width by 4, what will be the pe

rimeter of the new enlarged piece of wood?
A. 36 m
B. 48 m
C. 64 m
D. 72 m
Mathematics
2 answers:
masya89 [10]3 years ago
6 0

Answer:

c. 64 im sorry if its wrong

Step-by-step explanation:

aivan3 [116]3 years ago
5 0

Answer:

The answer is D. 72 m

Step-by-step explanation:

To find the answer, you need to know what the original perimeter is. Say the perimeter is 6+6+3+3. You multiply all of those numbers and you get 24+24+12+12. Add those together and you get 72.

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Factorize: x² + 3x + 2​
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Step-by-step explanation:

x² + 3x + 2

x² + x + 2x + 2 because 1+2=3 and 2×1=2

By taking out common terms, we get

x(x+1)+2(x+1)

(x+1)(x+2)

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If a consumer takes out a $100 payday loan, his total cost will be higher because of
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being smart

Step-by-step explanation:

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2 years ago
Evaluate 2y when y = 6
Alina [70]

\bf \red{answer}

When,

y=6

2y=2×6=12

4 0
3 years ago
How do you do this? Please give an example to #1 and explain thoroughly please. I have asked multiple times and gotten answers I
liberstina [14]

Answer:

y=2x

Step-by-step explanation:

y = kx is the format of the graph we are looking for (as told in the instructions) where k is the variable we are supposed to find (like y = x, y=2x, y=3x, etc)

Note that as x increases by 1, y increases by 2. We can see that by writing a table of the points of points that the line given intersects (picture below). We can see that by the values of the x-axis and the y-axis. Why does this happen? This is because y =2x for each value of x. We notice that in our table.

Therefore, the equation is y=2x. I hope this helps! If you still have questions, ask me in the comments!

4 0
3 years ago
A manufacturer uses production method to produce steel rods. A random sample of 17 steel rods resulted in lengths with a standar
Arisa [49]

Answer:

\chi^2 =\frac{17-1}{12.15} 22.09 =15.87

Traditional method

We can find a critical value in the chi square distribution with df =16 who accumulates \alpha/2 =0.05 of the area on each tail and we got:

\chi^2_{crit}= 7.962

\chi^2_{crit}=26.296

Since the calculated value is between the two critical values we don't have enough evidence to conclude that the true deviation is NOT significantly different from 3.5 cm

Confidence level method

We can find the p value like this

p_v =2*P(\chi^2 >15.87)=0.92

Since the p value is higher then the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is NOT significantly different from 3.5 cm

Step-by-step explanation:

Data provided

n=17 represent the sample selected

\alpha=0.1 represent the significance

s^2 =4.7^2 =22.09 represent the sample variance

\sigma^2_0 =3.5^2 =12.15 represent the value to check

Null and alternative hypothesis

We want to verify if the new production method has lengths with a standard deviation different from 3.5 cm, so the system of hypothesis would be:

Null Hypothesis: \sigma^2 = 12.15

Alternative hypothesis: \sigma^2 \neq 12.15

The statistic for this case is given by:

\chi^2 =\frac{n-1}{\sigma^2_0} s^2

The degrees of freedom are:

df =n-1= 17-1=16

\chi^2 =\frac{17-1}{12.15} 22.09 =15.87

Traditional method

We can find a critical value in the chi square distribution with df =16 who accumulates \alpha/2 =0.05 of the area on each tail and we got:

\chi^2_{crit}= 7.962

\chi^2_{crit}=26.296

Since the calculated value is between the two critical values we don't have enough evidence to conclude that the true deviation is significantly different from 3.5 cm

Confidence level method

We can find the p value like this

p_v =2*P(\chi^2 >15.87)=0.92

Since the p value is higher then the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is significantly different from 3.5 cm

7 0
3 years ago
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