Answer:
A
Explanation:
this because
gravitational potential energy = mass x height x gravitational field strength
so let's assume mass is 2 kg and gravitational field strength is 10 N /kg
so when height is very low, take it as 3 m
gravitational potential energy= 2 x 3 x 10 = 60 j
but when height is 6m
gravitational potential energy = 2 x 6 x 10 = 120 j
so when the height is the greatest, the gravitational potential energy is the highest
so A is the heighest so it has the highest gravitational potential energy.
hope this helps
please mark it brainliest :D
E=mgh. 196=5kg*9.81m/s^2*h. So h=196/(5*9.81)=4m
Answer:
x = 0.775m
Explanation:
Conceptual analysis
In the attached figure we see the locations of the charges. We place the charge q₃ at a distance x from the origin. The forces F₂₃ and F₁₃ are attractive forces because the charges have an opposite sign, and these forces must be equal so that the net force on the charge q₃ is zero.
We apply Coulomb's law to calculate the electrical forces on q₃:
(Electric force of q₂ over q₃)
(Electric force of q₁ over q₃)
Known data
q₁ = 15 μC = 15*10⁻⁶ C
q₂ = 6 μC = 6*10⁻⁶ C
Problem development
F₂₃ = F₁₃
(We cancel k and q₃)

q₂(2-x)² = q₁x²
6×10⁻⁶(2-x)² = 15×10⁻⁶(x)² (We cancel 10⁻⁶)
6(2-x)² = 15(x)²
6(4-4x+x²) = 15x²
24 - 24x + 6x² = 15x²
9x² + 24x - 24 = 0
The solution of the quadratic equation is:
x₁ = 0.775m
x₂ = -3.44m
x₁ meets the conditions for the forces to cancel in q₃
x₂ does not meet the conditions because the forces would remain in the same direction and would not cancel
The negative charge q₃ must be placed on x = 0.775 so that the net force is equal to zero.
Answer:
For instance, an object is moving and we can say that a force is acting or must have been acted upon to cause the state of motion. When force is applied, it changes the position of the object concerning time resulting in motion. The motion, in other words, is described as a change in speed or change in direction.