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aalyn [17]
3 years ago
10

Dos masas de 8kg es tan unidas en el extremo de una varilla de aluminio de 400mm de longitud. La varilla está sostenida en su pa

rte media hora en círculos y solo puede soportar una tensión máxima de 800 N ¿cuál es la frecuencia máxima de revolución
Physics
1 answer:
enyata [817]3 years ago
7 0

Answer:

The maximum frequency of revolution is 3.6 Hz.

Explanation:

Given that,

Mass = 8 kg

Distance = 400 mm

Tension = 800 N

We need to calculate the velocity

Using centripetal force

F=\dfrac{mv^2}{r}

Where, F= tension

m = mass

v= velocity

r = radius of circle

Put the value into the formula

800=\dfrac{8\times v^2}{200\times10^{-3}}

v^2=\sqrt{\dfrac{800\times200\times10^{-3}}{8}}

v=4.47\ m/s

We need to calculate the maximum frequency of revolution

Using formula of frequency

f=\dfrac{v}{2\pi r}

Put the value into the formula

f=\dfrac{4.47}{2\pi\times200\times10^{-3}}

f=3.6\ Hz

Hence, The maximum frequency of revolution is 3.6 Hz.

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The tops of the towers of the Golden Gate Bridge in San franciscoo , are 227 m above the water. Suppose a worker drops a 655 g w
yaroslaw [1]

Answer:

Kinetic energy is 1425.11 J.

Explanation:

Given:

Mass of the wrench is, m=655\ g=0.655\ kg

Height of fall is, h=227\ m

Force of resistance is, F=0.141\ N

Now, the total energy at the top is equal to the potential energy of the wrench at the top since the kinetic energy at the top is 0.

Now, potential energy at the top is given as:

U=mgh\\U=0.655\times 9.8\times 227\\U=1457.113\ J

Now, the potential energy at the top is converted to kinetic energy at the bottom and some energy is wasted in overcoming the resistance force by air.

Potential Energy = Kinetic energy + Energy to overcome resistance.

⇒ Kinetic energy = Potential Energy - Energy to overcome resistance.

Energy to overcome resistance force is the work done by the wrench against the resistance force and is given as:

W_{res}=Fh=0.141\times 227=32.007\ J

Therefore, Kinetic energy at the bottom is given as:

K=U-W_{res}\\\\K=1457.113\ J - 32.007\ J\\\\K=1425.106\approx1425.11\ J

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3 years ago
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A 40.0 kg wagon is towed up a hill inclined at 18.5 degrees with respect to the horizontal. The tow rope is parallel to the incl
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Answer:

7.9m/s

Explanation:

We are given that

Mass of wagon=40 kg

\theta=18.5^{\circ}

Tension=140 N

Initial velocity of wagon=u=0

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Net force applied  on wagon=F=T-mgsin\theta=140-40(9.8)sin18.5=15.7 N

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a=\frac{F}{a}=\frac{15.7}{40}=0.39m/s^2

We know that

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Using the formula

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