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Lana71 [14]
3 years ago
11

Which type of curved mirror uses its inside as the reflecting surface? A. a convex mirror B. a plane mirror C. a virtual mirror

D. a concave mirror

Physics
2 answers:
ser-zykov [4K]3 years ago
6 0

D. a concave mirror

natali 33 [55]3 years ago
5 0

Answer:

Concave Mirror

Explanation:

1).Concave Mirror

here the reflecting surface is curved inside then it is always concave mirror

2). Convex mirror

here the curved surface outwards will be the reflecting surface and focus is taken as negative as it always forms virtual image of smaller size.

3). Plane Mirror

here the reflecting surface is always plane surface and straight surface and its focus is infinite and always forms virtual image of same size

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Acceleration and Force
olga55 [171]

Answer:

I'm pretty sure its 3m/s^2 for the acceleration but I don't know the force part sorry .

Explanation:

15m/s - 0m/s divided by 5 s = 3m/s

I'm no expert or anything so I could be wrong but this is the best I can give you. Sorry

6 0
2 years ago
If a 2500 kg car is traveling with an acceleration of 20.2 m/s/s, what is the force acting on it?
a_sh-v [17]

Answer:

50500

Explanation:

F = m x a

F = 2500kg x 20.2 m/s/S

F = 50500

4 0
3 years ago
A man is walking while riding a train. He says he is moving at 2 mph. A woman standing on a platform at a train station says the
-BARSIC- [3]

The woman is correct because it is the pace he is moving not walking.

5 0
4 years ago
A wheel decelerates from 13.5 rad s−1 to 6.0 rad s−1 in 7 s. Calculate the angular displacement​
Igoryamba

Answer:

<em>Angular displacement=68.25 rad</em>

Explanation:

<u>Circular Motion</u>

If the angular speed varies from ωo to ωf in a time t, then the angular acceleration is given by:

\displaystyle \alpha=\frac{\omega_f-\omega_o}{t}

The angular displacement is given by:

\displaystyle \theta=\omega_o.t+\frac{\alpha.t^2}{2}

The wheel decelerates from ωo=13.5 rad/s to ωf=6 rad/s in t=7 s, thus:

\displaystyle \alpha=\frac{6-13.5}{7}

\displaystyle \alpha=\frac{-7.5}{7}

\displaystyle \alpha=-1.071 \ rad/s^2

Thus, the angular displacement is:

\displaystyle \theta=13.5*7+\frac{-1.071*7^2}{2}

\displaystyle \theta=94.5-26.25

\boxed{\displaystyle \theta=68.25\ rad}

Angular displacement=68.25 rad

3 0
3 years ago
A student moves a horseshoe magnet by hand across a tabletop to varying distances from an electromagnet, as shown in the diagram
Sloan [31]

The closer together they are the harder it is to hold on to because the magnetic field is stronger as it gets closer.


Answer:

D. The electromagnet's magnetic field is stronger close to it than far from it.​

4 0
2 years ago
Read 2 more answers
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