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Lana71 [14]
3 years ago
11

Which type of curved mirror uses its inside as the reflecting surface? A. a convex mirror B. a plane mirror C. a virtual mirror

D. a concave mirror

Physics
2 answers:
ser-zykov [4K]3 years ago
6 0

D. a concave mirror

natali 33 [55]3 years ago
5 0

Answer:

Concave Mirror

Explanation:

1).Concave Mirror

here the reflecting surface is curved inside then it is always concave mirror

2). Convex mirror

here the curved surface outwards will be the reflecting surface and focus is taken as negative as it always forms virtual image of smaller size.

3). Plane Mirror

here the reflecting surface is always plane surface and straight surface and its focus is infinite and always forms virtual image of same size

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A jet plane comes in for a downward dive as shown in the figure below.
xxTIMURxx [149]

The solution would be like this for this specific problem:

<span>5.5 g = g + v^2/r </span><span>
<span>4.5 g = v^2/r </span>
<span>v^2 = 4.5 g * r </span>
<span>v = sqrt ( 4.5 *9.81m/s^2 * 350 m) </span>
v = 124 m/s</span>

So the pilot will black out for this dive at 124 m/s. I am hoping that these answers have satisfied your query and it will be able to help you in your endeavors, and if you would like, feel free to ask another question.

8 0
3 years ago
Read 2 more answers
A running student has half the kinetic energy that his brother has. The student speeds up by 1 m/s, at which point he has the sa
hoa [83]

Answer:

V = (√2) + 1) m/s

Explanation:

Let the mass and speed of the running student be M and V respectively.

We are told that when he speeds up by 1 m/s, he has the same kinetic energy as his brother.

Thus, his speed at which he mow has the same kinetic energy as his brother is (V + 1) m/s

Now, we are told that the mass of the student is twice as large as that of his brother. Thus, his brother's mass is; M/2

Since kinetic energy is given by the formula K.E = ½mv²

Therefore, since we want to find the original speed of both students and that the initial condition says that the running student had half the kinetic energy of the brother, we now initial condition as;

½MV²= ½(½(M/2)V²) - - - - (eq 1)

Since he has sped up by 1 m/s, and has a kinetic energy now equal to that of his brother, we have;

(½M(V + 1)²) = (½(M/2)V²) - - - - (Eq2)

Dividing eq 1 by eq 2 gives;

V²/(V + 1)²= 1/2

Taking square root of both sides gives;

V/(V + 1) = 1/√2

Cross multiply to give;

(√2)V = V + 1

(√2)V - V = 1

V((√2) - 1) = 1

V = 1/((√2) - 1)

Simplifying this using surfs gives;

V = [1/((√2) - 1)] × ((√2) + 1))/((√2) + 1))

V = ((√2) + 1))/1

V = (√2) + 1) m/s

8 0
3 years ago
What happens as a result of the pulses passing by each other?
nadezda [96]

Answer:

After pulses pass through each other, each pulse continues along its original direction of travel, and their original amplitudes remain unchanged.

Explanation:

Constructive interference takes place when two pulses meet each other to create a larger pulse.

8 0
2 years ago
When a metal bonds with a nonmetal, they form a(n)
MArishka [77]
I believe it would be B.
5 0
3 years ago
A copper rod 0.570 � long and with a mass 0.05900 �� is suspended from two thin wire. At right angle to the rod is a uniform mag
finlep [7]

Answer:

a) Left to right

b) 1.51 A

Explanation:

a)

The gravitational force on the rod due to its mass is in downward direction. hence to levitate the rod, the magnetic force on the rod must be in upward direction.

The magnetic field is inward to page and magnetic force must be upward. Using right hand rule, the current must be flowing from left to right.

Left to right

b)

L = length of the copper rod = 0.570 m

m = mass of the rod = 0.059 kg

B = magnitude of magnetic field in the region = 0.670 T

θ = Angle between the magnetic field and rod = 90

i = current flowing throw the rod = ?

The magnetic force on the rod balances the gravitational force on the rod. hence

Magnetic force = gravitational force

mg = i B L Sinθ

(0.059) (9.8) = i (0.670) (0.570) Sin90

i = 1.51 A

6 0
3 years ago
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