Answer of your question is in this photo
Which type of curved mirror uses its inside as the reflecting surface? A. a convex mirror B. a plane mirror C. a virtual mirror
D. a concave mirror
2 answers:
Answer:
Concave Mirror
Explanation:
1).Concave Mirror
here the reflecting surface is curved inside then it is always concave mirror
2). Convex mirror
here the curved surface outwards will be the reflecting surface and focus is taken as negative as it always forms virtual image of smaller size.
3). Plane Mirror
here the reflecting surface is always plane surface and straight surface and its focus is infinite and always forms virtual image of same size
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Answer:
The ball would have landed 3.31m farther if the downward angle were 6.0° instead.
Explanation:
In order to solve this problem we must first start by doing a drawing that will represent the situation. (See picture attached).
We can see in the picture that the least the angle the farther the ball will go. So we need to find the A and B position to determine how farther the second shot would go. Let's start with point A.
So, first we need to determine the components of the velocity of the ball, like this:
we pick the positive one, so it takes 0.317s for the ball to hit on point A.
so now we can find the distance from the net to point A with this time. We can find it like this:
Once we found the distance between the net and point A, we can similarly find the distance between the net and point B:
t= -0.9159s or t=0.468s
we pick the positive one, so it takes 0.468s for the ball to hit on point B.
so now we can find the distance from the net to point B with this time. We can find it like this:
So once we got the two distances we can now find the difference between them:
so the ball would have landed 3.31m farther if the downward angle were 6.0° instead.
Answer:
1.75atm
Explanation:
According to Boyle's law, the pressure P of a fixed mass of gas is inversely proportional to it's volume V provided that the temperature remains constant.
This implies the following;
Provided temperature is kept constant.
Given;
From equation (1), we can write;
Since all the units are consistent, there is no need for conversion.