All categories

3 years ago

PLEASE HELP IN ONE MINUTE WILL MARK BRAINLIST ND GIVE MONEY

Mathematics

1 answer:

marusya05 [52]3 years ago

5 0

Answer:

Step-by-step explanation:

Please mark brainiest

You might be interested in

What is the answer to 1/4N=24

PilotLPTM [1.2K]

0.25*N=24
N=24/0.25
N=96

8 0

3 years ago

Read 2 more answers

Answer this will give 10 points

Travka [436]

Answer:

maximum --> 62

median --> 46.5

upper quartile --> 60

lower quartile --> 37

minimum --> 32

Step-by-step explanation:

Forgive me on the explanation as I'm a bit rusty on these types of problems.

First, we need to put the set of numbers in order -->

from: 34, 37, 39, 32, 48, 45, 53, 62, 58, 61, 60, 41 -->

to: 32, 34, 37, 39, 41, 45, 48, 53, 58, 60, 61, 62

maximum = biggest number => thus, 62

median = middle number in a sense => (45+48)/2 => thus, 46.5

upper quartile = median over the median => thus, 60

lower quartile = median under the median => thus, 37

minimum = lowest number => thus, 32

And there we have our 5 answers.

<u>Hope this helps!</u>

3 0

3 years ago

On a cell phone mapping app, 5cm represents 150 feet. Which equation represents this relationship?

AnnZ [28]

Answer:

b cuz 150/5=3 :)

Step-by-step explanation:

cuz 150/5=3 :)

6 0

3 years ago

Applying properties of Exponents In Exercise, use the properties of exponents to simplify the expression.

eimsori [14]

Answer:

(a) $5^{8}$

(b) 3

(d) $\dfrac{1}{6}$

Step-by-step explanation:

We need simplify the given expressions.

(a)

Consider the given expression is

$(5^4)(25^2)$

$(5^4)((5^2)^2)$

Using the properties of exponents we get

$(5^4)(5^4)$ $[\because (a^m)^n=a^{mn}]$

$5^{4+4}$ $[\because a^ma^n=a^{m+n}]$

$5^{8}$

(b)

Consider the given expression is

$(9^{\frac{1}{3}})(3^{\frac{1}{3}})$

$((3^2)^{\frac{1}{3}})(3^{\frac{1}{3}})$

Using the properties of exponents we get

$(3^{\frac{2}{3}})(3^{\frac{1}{3}})$ $[\because (a^m)^n=a^{mn}]$

$3^{\frac{2}{3}+\frac{1}{3}}$ $[\because a^ma^n=a^{m+n}]$

$3^{1}$

$3$

(c)

Consider the given expression is

$(\dfrac{1}{3})^{-3}$

Using the properties of exponents we get

$(\dfrac{3}{1})^{3}$ $[\because a^{-n}=\dfrac{1}{a^n}]$

$3^{3}$

$27$

(d)

Consider the given expression is

$(6^4)(6^{-5})$

Using the properties of exponents we get

$6^{4+(-5)}$ $[\because a^ma^n=a^{m+n}]$

$6^{-1}$

$\dfrac{1}{6^{1}}$ $[\because a^{-n}=\dfrac{1}{a^n}]$

$\dfrac{1}{6}$

6 0

3 years ago

Investment A 50 increases each year by 8% investment B 60 increases by 3 each year what year will investment A be bigger than be

UkoKoshka [18]

Answer:

After 10 years the investment A will be bigger than investment B.

Step-by-step explanation:

In Investment A, 50 increases each year by 8% and in investment B, 60 increases by 3 each year.

If after x years the investment A will be equal to investment B, then we can write the equation as

$50(1 + \frac{8 \times x}{100}) = 60 + 3x$

⇒ 50 + 4x = 60 + 3x

⇒ x = 10

Therefore, after 10 years the investment A will be bigger than investment B. (Answer)

6 0

3 years ago