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4vir4ik [10]
3 years ago
8

What does it mean for two fractions to be equivalent? For two ratios to be equivalent?

Mathematics
1 answer:
nadya68 [22]3 years ago
6 0
When two fractions are equivalent that means that different fractions have the same number
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Root99 + root44<br> can someone help?
iogann1982 [59]

Answer:

here I worked it out on my calculator so it should be right

5 root 11

6 0
2 years ago
Steel is formed by combining masses of carbon and iron in the ratio 1:49. How many pounds of iron would it take to create 10 pou
Sergeu [11.5K]

Answer:

9.8

Step-by-step explanation:

1:49= ratio of carbon to to iron

1+49= steel

50=10pounds

49=?pounds

49 * 10/50

=49/5

=9.8pounds

4 0
3 years ago
Principle = 30,000<br>Time = 4 years<br>Rate = 30<br>Then find the simple interest ?​
Nutka1998 [239]

Answer:

\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{Given:}}}}}}\end{gathered}

  • {\dashrightarrow \sf{Principle = Rs.30000}}
  • {\dashrightarrow \sf {Time = 4 \: years}}
  • \dashrightarrow \sf{Rate = 30\%}
  • \begin{gathered}\end{gathered}

\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{To Find:}}}}}}\end{gathered}

  • \dashrightarrow{\sf{Simple \: Interest }}

\begin{gathered}\end{gathered}

\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{Using Formula:}}}}}}\end{gathered}

\dag{\underline{\boxed{\sf{ S.I = \dfrac{P \times R \times T}{100}}}}}

Where

  • \dashrightarrow{\sf{S.I = Simple \:  Interest }}
  • {\dashrightarrow{\sf{P = Principle }}}
  • {\dashrightarrow{\sf{ R = Rate }}}
  • {\dashrightarrow{\sf{T = Time}}}

\begin{gathered}\end{gathered}

\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{Solution:}}}}}}\end{gathered}

{\quad {: \implies{\sf{ S.I =  \bf{\dfrac{P \times R \times T}{100}}}}}}

Substituting the values

{\quad {: \implies{\sf{ S.I =  \bf{\dfrac{30000 \times 30\times 4}{100}}}}}}

{\quad {: \implies{\sf{ S.I =  \bf{\dfrac{30000 \times 120}{100}}}}}}

{\quad {: \implies{\sf{ S.I =  \bf{\dfrac{3600000}{100}}}}}}

{\quad {: \implies{\sf{ S.I =  \bf{\cancel{\dfrac{3600000}{100}}}}}}}

{\quad {: \implies{\sf{ S.I =  \bf{Rs.36000}}}}}

{\dag{\underline{\boxed{\sf{ S.I ={Rs.36000}}}}}}

  • Henceforth,The Simple Interest is Rs.36000..

\begin{gathered}\end{gathered}

\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{Learn More:}}}}}}\end{gathered}

\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered} \dag \: \underline{\bf{More \: Useful \: Formula}}\\ {\boxed{\begin{array}{cc}\dashrightarrow {\sf{Amount = Principle + Interest}} \\ \\ \dashrightarrow \sf{ P=Amount - Interest }\\ \\ \dashrightarrow \sf{ S.I = \dfrac{P \times R \times T}{100}} \\ \\ \dashrightarrow \sf{P = \dfrac{Interest \times 100 }{Time \times Rate}} \\ \\ \dashrightarrow \sf{P = \dfrac{Amount\times 100 }{100 + (Time \times Rate)}} \\ \end{array}}}\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}

8 0
3 years ago
Read 2 more answers
What is an equation of the line that passes through the points (0, -1)(0,−1) and (6, 1)(6,1)?
horrorfan [7]

slope = y2 - y1 \div x2 - x1

1 -  - 1 \div 6 - 0

2 \div 6

1 \div 3

y = mx + c

1 = 1 \div 3 \times 6 + c

1 = 2 + c

c = 3

y = 1 \div 3x + 3

5 0
3 years ago
Line ET is tangent to circle A at point T and the measure of angle TNG is 35.
STALIN [3.7K]

ET is tangent to circle A so ET is perpendicular to AT

So <ATE = 90°

Given <TNG = 35°

<NET = <ATE - <TNG

= 90° - 35°

= 55°

Answer is 55°

8 0
3 years ago
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