$\frac{4 + 3y}{6y - 2} = \frac{ - 3}{5} \\ \\ - 3(6y - 2) = 5(4 + 3y) \\ \\ - 18y + 6 = 20 + 15y \\ \\ 15y + 18y = 6 - 20 \\ \\ 33y = - 14 \\ \\ y = \frac{ - 14}{33} \\ \\ y = - 0.42$

I hope I helped you^_^

8 0

2 years ago

Read 2 more answers

Pls help meeeeeeee pls pls pls

Rom4ik [11]

Answer:

D. $\frac{4x^{2} \sqrt{29}}{29}$

Step-by-step explanation:

Given the expression:

$\frac{40x^{2} \sqrt{x^{12} } }{10x^{2} \sqrt{29x^{8} } }$

divide by the common factor to have;

$\frac{4\sqrt{x^{12} } }{\sqrt{29x^{8} } }$ = $\frac{4(x^{12}) ^{\frac{1}{2} } }{(29x^{8}) ^{\frac{1}{2} } }$

= $\frac{4x^{6} }{\sqrt{29}x^{4} }$

= $\frac{4x^{2} }{\sqrt{29} }$

Rationalize the denominator, we have;

$\frac{4x^{2} }{\sqrt{29} }$ x $\frac{\sqrt{29} }{\sqrt{29} }$

So that,

$\frac{4x^{2} \sqrt{29} }{29}$

Thus,

$\frac{40x^{2} \sqrt{x^{12} } }{10x^{2} \sqrt{29x^{8} } }$ = $\frac{4x^{2} \sqrt{29} }{29}$

The correct option is D.

5 0

2 years ago