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2 years ago

How do I find the area of a trapezoid?

Mathematics

1 answer:

konstantin123 [22]2 years ago

3 0

Answer:

Step-by-step explanation:

Area of a trapezoid is found with the formula, A=(a+b)/2 x h. Learn how to use the formula to find area of trapezoids.

The two parallel sides are the bases, and height, as always, is the perpendicular distance from one base to the opposite. The area of this parallelogram is its height (half-height of the trapezoid) times its base (sum of the bases of the trapezoid), so its area is half-height × (base1 + base2).

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What two step equation when solved does x=-3

Travka [436]

Answer:

x + 3 = 0.

Step-by-step explanation:

One would be:

x + 3 = 0 Subtract 3 from both sides:

x + 3 - 3 = 0 - 3

x = -3

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2 years ago

The U.S. Senate has 100 members. After a certain election, there were 4 more Democrats than Republicans, with no other parties r

kakasveta [241]

Let x = # of Republicans

x + 4 = # of Democrats

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There are 52 Democrats and 48 Republicans.

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2 years ago

The gas law for an ideal gas at absolute temperature T (in kelvins), pressure P (in atmospheres), and volume V (in liters) is PV

JulijaS [17]

Answer:

$\frac{dT}{dt}=3.78^{\circ}K/min$

Step-by-step explanation:

We have to calculate the time derivative of T=PV/nR with P and V variable and n and R constants. This is:

$\frac{dT}{dt} =\frac{d\frac{PV}{nR}}{dt}=\frac{1}{nR}\frac{d(PV)}{dt}$

What we have to do is the derivative of a product:

$\frac{d(PV)}{dt}=P\frac{dV}{dt}+V\frac{dP}{dt}$

Substituting, we have:

$\frac{dT}{dt} =\frac{P\frac{dV}{dt}+V\frac{dP}{dt}}{nR}$

where all these values are given since the time derivatives of P and V are their variation rate, using minutes.

We then substitute everything, noticing that already everything is in the same system of units so they cancel out:

$\frac{dT}{dt}=\frac{P\frac{dV}{dt}+V\frac{dP}{dt}}{nR}=\frac{(8atm)(0.16L/min)+(13L)(0.14atm/min)}{(10mol)(0.0821Latm/mol^{\circ}K)}$

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3 years ago

What is m<4+m<5+m<6?

viktelen [127]

Answer:

Step-by-step explanation:

$m$

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2 years ago

In the figure below, BD and EC are diameters of circle P. What is the arc measure of ADE in degrees? IMAGE BELOW

Pani-rosa [81]

Answer:

The arc measure of ∠ADE is equal to 333 degrees.

Step-by-step explanation:

Please refer to the attached diagram,

Let the unknown angle ∠APE = x

Since BD is the diameter of the circle then

∠APE + ∠DPE + ∠APB = 180°

∠APE + 63° + 90° = 180°

x + 63° + 90° = 180°

Solving for x

x = 180° - 90° - 63°

x = 90° - 63°

x = 27°

Since a circle has 360° then

∠ADE + ∠APE = 360°

∠ADE + x = 360°

∠ADE + 27° = 360°

∠ADE = 360° - 27°

∠ADE = 333°

Therefore, the arc measure of ∠ADE is equal to 333 degrees.

8 0

2 years ago

How do I find the area of a trapezoid?​

How do I find the area of a trapezoid?