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jeyben [28]
3 years ago
7

PLEASE HELP! DUE TODAY!

Mathematics
2 answers:
Kitty [74]3 years ago
4 0

Answer:

but it I'd not see your question

SVEN [57.7K]3 years ago
3 0

Answer:

post question plz

Step-by-step explanation:

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you need to clear up the graphics its all blurry.

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3 years ago
Tim made 4 stacks of wooden blocks. The first stack was 4 blocks tall. The second stack was 6 blocks taller than the first. The
Troyanec [42]
Tim used 26 blocks of wood
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4 years ago
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Find the greatest common factor : 25p^2q^3, 15p^2q^2 and 35pq^4
olga nikolaevna [1]

Answer:

The greatest common factor is 5pq^2.

Step-by-step explanation:

The given expressions are 25p^2q^3, 15p^2q^2 and 35pq^4.

Greatest common factor of two numbers is the greatest number that divides both numbers completely.

Find factors of each expression.

25p^2q^3=5\times 5\times p\times p\times q\times q\times q

15p^2q^2=3\times 5\times p\times p\times q\times q

35pq^4=5\times 7\times p\times q\times q\times q\times q

The common factors are 5,p,q and q. So, the greatest common factor of given expressions is

G.C.F.=5\times p\times q\times q

G.C.F.=5pq^2

Therefore the greatest common factor is 5pq^2.

3 0
3 years ago
A particle is moving with the given data. Find the position of the particle. a(t)=10sin(t)+3cos(t) s(0)=0 s(2pi)=12
zubka84 [21]
a(t)=10\sin t+3\cos t

v(t)=\displaystyle\int a(t)\,\mathrm dt
v(t)=\displaystyle\int(10\sin t+3\cos t)\,\mathrm dt
v(t)=-10\cos t+3\sin t+C_1

s(t)=\displaystyle\int v(t)\,\mathrm dt
s(t)=\displaystyle\int(-10\cos t+3\sin t+C_1)\,\mathrm dt
s(t)=-10\sin t-3\cos t+C_1t+C_2

With the boundary conditions s(0)=0 and s(2\pi)=12, we have

\begin{cases}0=-3+C_2&s(0)=0\\12=-3+2\pi C_1+C_2&s(2\pi)=12\end{cases}\implies C_1=\dfrac6\pi,C_2=3

so that the position of the particle is given by

s(t)=-10\sin t-3\cos t+\dfrac{6t}\pi+3
3 0
4 years ago
The height of the water in an above ground pool is 3
Firdavs [7]

<em>It will take 6 minutes to drain the pool.</em>

<h2>Explanation:</h2>

As the problem states the height of the water in an above ground pool is 3ft. In other word:

  • 3 ft is our starting point.

The pool needs to be drained at a Rate of Change of 1/2 inches per minutes. In other words:

  • The rate of change is constant, so we'll have a line with slope -1/2.

Therefore, we can write an equation as:

h=3-\frac{1}{2}t \\ \\ \\ h:Height \\ \\ t:time \\ \\ \\ The \ slope \ is \ negative \ because \ the \ pool \ needs \ to \ be \ drained

To drain the pool implies that we don't have any water in the pool, in other words this is true if and only if:

h=0

So:

h=3-\frac{1}{2}t \\ \\0=3-\frac{1}{2}t \\ \\ \\ Solving \ for \ t: \\ \\ \frac{1}{2}t=3 \\ \\ t=6

So, <em>it will take 6 minutes to drain the pool.</em>

<h2>Learn more:</h2>

Average Rate of Change: brainly.com/question/14196399#

#LearnWithBrainly

8 0
4 years ago
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