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3 years ago

For every 4 back handsprings Kayla completed, Rose did 5. If Rose completed 15 handsprings, how many did Kayla complete?

Mathematics

1 answer:

bazaltina [42]3 years ago

6 0

Answer:

Step-by-step explanation:

Since Rose did 15, she did 5 three times. Since Kayla does 4 for every 5 Rose does, she did 4 * 3, or 12 handsprings

Hopefully this helps, let me know if you have any other questions!

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Write an equation of the line that passes through the point (2,3) with slope 3.

djyliett [7]

Answer:

Step-by-step explanation:

The slope-intercept form of an equation of a line:

$y=mx+b$

m - slope

b - y-intercept

We have the slope m = 3, and the point (2, 3).

Put the value of slope and the coordinates of the given pint (x = 2, y = 3) to the equation of a line:

$3=3(2)+b$

$3=6+b$ subtract 3 from both sides

$-3=b\to b=-3$

Finally:

$y=3x-3$

5 0

3 years ago

The capacity of jose's vase is 2419 milliliters of water. he poured 1 liter 299 milliliters of water into the empty vase. then,

gogolik [260]

One liter is 1,000 ml. plus 299 ml. is 1,299 ml. plus the additonal 398 ml. is 1,697 ml. which is 722 ml. less than the total volume. (722 ml. of water can still be added.)

3 0

3 years ago

Number 1 and 2 please (25 points)

Elenna [48]

Answers:

1) $(3x+2)+(4-5x)=-2x+6$

$(3+2i)+(4-5i)=7-3i$

2) $(1-3x)(2+x)=-3x^{2}-5x+2$

$(1-3i)+(2+i)=5-5i$

Step-by-step explanation:

In mathematics there are rules related to complex numbers, specifically in the case of addition and multiplication:

Addition:

If we have two complex numbers written in their binomial form, the sum of both will be a complex number whose real part is the sum of the real parts and whose imaginary part is the sum of the imaginary parts (similarly as the sum of two binomials).

For example, the addition of these two binomials is:

$(3x+2)+(4-5x)=3x-5x+2+4=-2x+6$

Similarly, the addition of two complex numbers is:

$(3+2i)+(4-5i)=3+4+2i-5i=7-3i$ Here the complex part is the number with the $i$

Multiplication:

If we have two complex numbers written in their binomial form, the multiplication of both will be the same as the multiplication (product) of two binomials, taking into account that $i^{2}=-1$ .