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Llana [10]
3 years ago
7

QUESTION 1

Mathematics
1 answer:
Aloiza [94]3 years ago
8 0

Answer:

None of them are correct

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Please if someone could help me that would be greatly appreciated.
mariarad [96]

Answer:

Me

Step-by-step explanation:

5 0
3 years ago
Please solve this problem because tomorrow is my exam.<br><br>​
jonny [76]

Step-by-step explanation:

a). A = {x  ∈ R  I  5x-8 < 7}

5x - 8 < 7 <=> 5x < 8+7  <=> 5x < 15  =>

x < 3  => A = (-∞ ; 3)

A ∩ N = {0 ; 1 ; 2}

A - N* = (-∞ ; 3) - {1 ; 2}

b).  A = { x ∈ R  I  7x+2 ≤ 9}

7x+2 ≤ 9 <=> 7x ≤ 7  => x ≤ 1 => x ∈ (-∞ ; 1]

A ∩ N = {0 ; 1}

A-N* = (-∞ ; 1)

c). A = { x ∈ R  I  I 2x-1 I < 5}

I 2x-1 I < 5  <=> -5 ≤ 2x-1 ≤ 5  <=>

-4 ≤ 2x ≤ 6  <=> -2 ≤ x ≤ 3  => x ∈ [-2 ; 3]

A ∩ N = {0 ; 1 ; 2 ; 3}

A - N* = [-2 ; 3) - {1 ; 2}

d). A = {x ∈ R I I 6-3x I ≤ 9}

I 6-3x I ≤ 9  <=> -9 ≤ 6-3x ≤ 9  <=>

-15 ≤ -3x ≤ 3 <=> -5 ≤ -x ≤ 3  =>

-3 ≤ x ≤ 5  => x ∈ [-3 ; 5]

A ∩ N = {0 ; 1 ; 2 ; 3 ; 4 ; 5}

A - N* = [-3 ; 5) - {1 ; 2 ; 3 ; 4}

4 0
3 years ago
Real World Scenario:
iragen [17]

The distance of a train from the city depends on the speed, the time of

travel, and direction of motion of the train.

Correct responses:

  • Distance Train A is from the city: <u>750 - 75·t</u>
  • Distance Train B is from the city: 50·t
  • After <u>six</u> hours, the two trains are the same distance from the city
  • At that time both trains will be <u>300</u> miles away

1) From the time of departure of Train B to just before 6 hours after Train B's departure; 0 ≤ t < 6 hours

2) At time period, t > 6 hours

3) 250 miles

<h3>Method used to find the above response</h3>

Given:

The distance of train A from the city = 750 miles

Speed of train A = 75 mph

Time at which Train B leaves the city = When Train A is 750 miles from the city

Speed of Train B = 50 mph

Solution:

The equations are;

  • Distance of Train A from the city is; <u>x₁ = 750 - 75·t</u>
  • Distance of Train B from the city is <u>x₂ = 50·t</u>

When the train are the same distance from the city, we have;

750 - 75·t = 50·t

750 = 50·t + 75·t = 125·t

Therefore;

  • t = \mathbf{\dfrac{750}{125}} = 6

The time it takes the two trains to be the same distance from the city is 6 hours.

Which gives;

  • After <u>6</u> hours, the two trains are the same distance from the city.

The distance the trains will be after 6 hours is therefore;

750 - 75 × 6 = 300

The distance of the trains from the city after 6 hours = 300 miles

Therefore, we have;

  • At that time both trains will be <u>300</u> miles away

1) The time period Train A is further from the city is before the first 6 hours elapse; <u>0 hours ≤ t < 6 hours</u>

2) The Train B is further from the city after 6 hours of its departure from the city; <u>t > 6 hours</u>

3) The distance of Train A from the city after 4 hours is given as follows;

x₁ = 750 - 75 × 4 = 450

x₁ = 450 miles

The distance of Train B from the city after 4 hours is; x₂ = 50 × 4 = 200

x₂ = 200 miles

Therefore;

  • The distance between the trains after 4 hours = 450 miles - 200 miles = <u>250 miles</u>

Learn more about distance and time relationship equation here:

brainly.com/question/10804931

3 0
2 years ago
HELP HELP HELP , I WILL MARK BRAINLIEST!!
Nataly [62]

Answer:

c

Step-by-step explanation:

3 0
3 years ago
Solve 3m- 5h = 45 for h
Masja [62]

3m- 5h = 45\\5h=3m-45\ /:5\\h=\frac{3m-45}{5}\ \ \ or\ \ \ h=\frac{3}{5}m-9

4 0
3 years ago
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