X=1/2 I’m mostly guessing but for math just use the app called photo math it’s helps with math equations but not math written problems
Actually the position function with respect to time under constant acceleration is:
a=g
v=⌠g dt
v=gt+vi
s=⌠v
s=gt^2/2+vit+si
So if vi and si are zero then you just have:
s=gt^2/2
Notice that it is not gt^2 but (g/2) t^2
So the first term in any quadratic is half of the acceleration times time squared because of how the integration works out...
Anyway....
sf=(a/2)t^2+vit+si
(sf-si)-vit=a(t^2)/2
2(sf-si)-2vit=at^2
a=(2(sf-si)-2vit)/t^2 and if si and vi equal zero
a=(2s)/t^2
Problem: 2x^2+3x-9
For a polynomial of the form, ax^2+bx+c rewrite the middle term as the sum of two terms whose product a·c=2·-9=-18 and whose sum is b=3.
Factor 3 out of 3x
2x^2+3(x)-9
Rewrite 3 as -3 plus 6.
2x^2+(-3+6)x-9
Apply the distributive property
2x^2(-3x+6x)-9
Remove the parentheses
2x^2-3x+6x-9
Factor out the greatest common factor from each group
Group the first two terms and the last two terms
(2x^2-3x) (6x-9)
Factor out the greatest common factor in each group.
x(2x-3)+3(2x-3)
Factor the polynomial by factoring out the greatest common factor, 2x-3
(x+3) (2x-3). So, the quotient is 2x-3
Answer:
The length of the longest section x = 36 ft
Step-by-step explanation:
Total length of the wire = 51 ft
Let first section of wire = x
Second section of wire = y
Third section of wire = z
According to given data
x = 3 y & y = 4 z
Total length of the wire = x + y + z = 51
y = 12
x = 3 × 12 = 36
Therefore the length of the longest section x = 36 ft
Answer:
The square root of 45
Step-by-step explanation:
9^2-6^2=c^2
81-36=c^2
45=c^2
c=sqrt(45)
