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2 years ago

Solve 0.667a+5=1.667a

Mathematics

2 answers:

Colt1911 [192]2 years ago

4 0

The answer to your question is a=5 because if you times some other numbers with it it means you will get that a=5. xoxo

Angelina_Jolie [31]2 years ago

3 0

<span>0.667a+5=1.667a
</span>0.667a - 1.667a = -5
- 1a = -5
a = 5

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Solve using any method. All work must be shown and handwritten.

Rashid [163]

Answer:

$x = - 3$

$y = 1$

Step-by-step explanation:

Write the system

$3x - y = - 10$

$x + y = - 2$

Solve by Elimination.

multiply the second equation by -3.

$3x - y = - 10$

$-3x - 3y = 6$

Add the Equations.

$- 4y = - 4$

$y = 1$

Plug this back in one of the equations.

$x + 1 = - 2$

$x = - 3$

8 0

2 years ago

Read 2 more answers

Find the measures of an interior angle and an exterior angle of a regular hexagon. The measure of an interior angle is 120. The

Tom [10]

Answer:

see explanation

Step-by-step explanation:

Since a hexagon has 6 interior angles and the measure of one is 120°, then

sum of interior angles = 6 × 120° = 720°

exterior angle = 180° - interior angle = 180° - 120° = 60°

7 0

2 years ago

A man travels 20 km by car from Town P to Town Q at an average speed of x km/h. He finds that the time of the journey would be s

yuradex [85]

Answer:

x = 20.

Step-by-step explanation:

First, you should remember the relation:

Distance = Speed*Time.

First, we know that a man travels a distance of 20km at a speed of x km/h, in a time T.

We can write this as:

20km = (x km/h)*T

We know that the time is shortened by 12 minutes if the speed is increased by 5km/h

Rewriting these 12 minutes in hours (remember that 60min = 1 hour)

12 min = (12/60) hours = 0.2 hours

Then from this, he can travel the same distance of 20km in a time T minus 0.2 hours if the speed is increased by 5 km/h

We can write this as:

20km = (x + 5 km/h)*(T - 0.2 h)

Then we have a system of two equations, and we want to find the value of x:

20km = (x km/h)*T

20km = (x + 5 km/h)*(T - 0.2 h)

First, we should isolate the variable T in one of the equations, if we isolate it in the first one, we will get:

20km/(x km/h) = T

Replacing that in the other equation we get:

20km = (x + 5 km/h)*(T - 0.2 h)

20km = (x + 5 km/h)*( 20km/(x km/h) - 0.2 h)

Now we can solve this for x.

Removing the units (that we know that are correct) so the math is easier to read, we get:

20 = (x + 5)*(20/x - 0.2)

We only want to solve this for x.

20 = x*20/x - x*0.2 + 5*20/x - 5*0.2

20 = 20 - 0.2*x + 100/x - 1

subtracting 20 in both sides we get:

20 - 20 = 20 - 0.2*x + 100/x - 1 - 20

0 = -0.2*x + 100/x - 1

If we multiply both sides by x we get:

0 = -0.2*x^2 + 100 - x

-0.2*x^2 - x + 100 = 0

This is just a quadratic equation, we can solve it using the Bhaskara's equation, the solutions are:

$x = \frac{-(-1) \pm \sqrt{(-1)^2 - 4*(-0.2)*100} }{2*-0.2} = \frac{1 \pm 9 }{-0.4}$

Then the two solutions are:

x = (1 + 9)/-0.4 = -25

x = (1 - 9)/-0.4 = 20

As x is used to represent a speed, the negative solution does not make sense, so we should use the positive one.

x = 20

then the average speed initially is 20 km/h

3 0

2 years ago

A chef got 7 bags of onions. The red onions came in bags of 8 and the yellow onions came in bags of 3. If the chef got a total o

frutty [35]

Answer:

$\#\text{ of 8-onion bags: }4,\\\#\text{ of 3-onion bags: }3$

Step-by-step explanation:

Let $a$ be the number of bags with 8 onions and let $b$ be the number of bags with 3 onions. We have the following system of equations:

$\begin{cases}a+b=7,\\8a+3b=41\end{cases}$

Subtracting $b$ from both sides of the first equation, we get $a=7-b$ . Substitute this into the second equation:

$8(7-b)+3b=41,\\56-8b+3b=41,\\56-5b=41,\\-5b=-15,\\b=\boxed{3}$

Therefore, the number of 8-onion bags is:

$a=7-b,\\a=7-3,\\a=\boxed{4}$

Thus, the chef got 4 8-onion bags and 3 3-onion bags.

5 0

3 years ago

Write 9 41/80 as a decimal

jolli1 [7]

Leave the whole number alone for now. Divide 41 by 80 and you get 0.5125

So your answer is 9.5125

6 0

3 years ago