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Readme [11.4K]
2 years ago
7

12000 is invested at a 10% rate compounded for 15years

Mathematics
2 answers:
Olin [163]2 years ago
8 0

Answer:

$88,292

Step-by-step explanation:

answer was asked to my teacher she told me it was that   hope this helps you :)

Deffense [45]2 years ago
5 0

Answer:

50126.978033

Step-by-step explanation:

12000(1.10)^15

12000 is your starting amount.

You earning 10% investment so add 1 to that 10% and make it a decimal = 1.10

Raise is to 15 years because it's compounded for 15 years.

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Is 12/17 equivalent to 10/15 in ratio form
serg [7]

Answer: yes

Step-by-step explanation: Joshua

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3 years ago
The equation tan^2 x+1=sec^2 x is an identity true or false
Solnce55 [7]

Answer:

tan²x + 1 = sec²x is identity

Step-by-step explanation:

* Lets explain how to find this identity

∵ sin²x + cos²x = 1 ⇒ identity

- Divide both sides by cos²x

∵ sin x ÷ cos x = tan x

∴ sin²x ÷ cos²x = tan²x

- Lets find the second term

∵ cos²x ÷ cos²x = 1

- Remember that the inverse of cos x is sec x

∵ sec x = 1/cos x

∴ sec²x = 1/cos²x

- Lets write the equation

∴ tan²x + 1 = 1/cos²x

∵ 1/cos²x = sec²x

∴ than²x + 1 = sec²x

- So we use the first identity sin²x + cos²x = 1 to prove that

 tan²x + 1 = sec²x

∴ tan²x + 1 = sec²x is identity

8 0
3 years ago
What is 13x13??????????????
nirvana33 [79]
The answer is 169 ..... I hope this helps :)

5 0
3 years ago
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How to evaluate the limit
anzhelika [568]
\displaystyle\lim_{x\to2}\frac{x^2-x+6}{x+2}

Both the numerator and denominator are continuous at x=2, which means the quotient rule for limits applies:

\dfrac{\displaystyle\lim_{x\to2}(x^2-x+6)}{\displaystyle\lim_{x\to2}(x+2)}=\dfrac{2^2-2+6}{2+2}=\dfrac84=2

Perhaps you meant to write that x\to-2 instead? In that case, you would have

\displaystyle\lim_{x\to-2}\frac{x^2-x+6}{x+2}=\lim_{x\to-2}\frac{(x+2)(x-3)}{x+2}=\lim_{x\to-2}(x-3)=-2-3=-5
4 0
3 years ago
Help with number 4,5,6 and 7 plz help this is really hard I fell asleep in class plz plz help
Katen [24]
4. 6/8, 5. 3 5/8, 6. 7 7/8, 7. 72 months and 2,190 days
8 0
3 years ago
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