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3 years ago

H(t)=16t^2+604 find how long it'll take to get the 348 feet

1 answer:

n200080 [17]3 years ago

6 0

I believe you meant - 16t^2 + 604 ft. If you leave that - sign out, this function will never equal 348 feet.

-16t^2 + 604 = 348 can be solved:

-16t^2 = -256 ft, and t = 16 sec. Whatever you are throwing will first rise, reach some max. value, and then begin falling, and eventually reach 348 ft.

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Si un cono lo obtienes haciendo girar un triángulo rectángulo cuya base es de 10cm y su altura es de 16cm ¿cuánto mide el radio

rodikova [14]

Answer:

10 cm.

Step-by-step explanation:

In order to better understand this question, I will attach an allusive image to the question.

Keep in mind that in this case the base of the triangle is equal to the radius of the base of the cone since the triangle rotates on its own axis, therefore the measurement of the base corresponds to 10 cm, therefore the radius measures 10 cm.

5 0

3 years ago

Factor -1/4 out of -1/2x -5/4y. (i will mark brainlyest)

mash [69]

Answer:

-1/4 (2x - 5y)

Step-by-step explanation:

For us to factor -1/4 out of -1/2x -5/4y

We will have to multiply the values in bracket by the reciprocal of -1/4 i.e -4 as shown

-1/2x - 5/4 y

= -1/4 (-4(-1/2x) - (-4)(-5/4y))

= -1/4 (4/2 x - 20/4 y)

= -1/4 (2x - 5y)

Hence the factored expression is -1/4 (2x - 5y)

5 0

3 years ago

Please help lol ....

Nataly [62]

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8 0

3 years ago

One gallon is 3.8 litres. How many litres will you need for 675 square ft? Show your work!

vazorg [7]

Answer:

2565 square ft

Step-by-step explanation:

675 x 3.8 = 2565 square feet

6 0

3 years ago

Terry and Callie do word processing. For a certain prospectus Callie can prepare it two hours faster than Terry can. If they wor

Dahasolnce [82]

Time taken by jerry alone is 10.1 hours

Time taken by callie alone is 8.1 hours

Solution:

Given:- For a certain prospectus Callie can prepare it two hours faster than Terry can

Let the time taken by Terry be "a" hours

So, the time taken by Callie will be (a-2) hours

Hence, the efficiency of Callie and Terry per hour is $\frac{1}{a-2} \text { and } \frac{1}{a} \text { respectively }$

If they work together they can do the entire prospectus in five hours

$\text {So, } \frac{1}{a-2}+\frac{1}{a}=\frac{1}{5}$

On cross-multiplication we get,

$\frac{a+(a-2)}{(a-2) \times a}=\frac{1}{5}$

$\frac{2 a-2}{(a-2) \times a}=\frac{1}{5}$

On cross multiplication ,we get

$\begin{array}{l}{5 \times(2 a-2)=a \times(a-2)} \\\\ {10 a-10=a^{2}-2 a} \\\\ {a^{2}-2 a-10 a+10=0} \\\\ {a^{2}-12 a+10=0}\end{array}$

using quadratic formula:-

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

$x=\frac{12 \pm \sqrt{144-40}}{2}$

$\begin{array}{l}{x=\frac{12 \pm \sqrt{144-40}}{2}} \\\\ {x=\frac{12 \pm \sqrt{104}}{2}} \\\\ {x=\frac{12 \pm 2 \sqrt{26}}{2}} \\\\ {x=6 \pm \sqrt{26}=6 \pm 5.1} \\\\ {x=10.1 \text { or } x=0.9}\end{array}$

If we take a = 0.9, then while calculating time taken by callie = a - 2 we will end up in negative value

Let us take a = 10.1

So time taken by jerry alone = a = 10.1 hours

Time taken by callie alone = a - 2 = 10.1 - 2 = 8.1 hours

3 0

3 years ago