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omeli [17]
3 years ago
13

04.01)Which unit rate is the lowest price per ounce? Choice A: 15 ounces of chocolate chips for $2.49 Choice B: 20 ounces of cho

colate chips for $3.32 Choice A Choice B The unit rates are equal. The unit rates cannot be determined.
Mathematics
2 answers:
EleoNora [17]3 years ago
8 0

The answer choice below (or above) me is correct I beleive I just wanted to show proof.

15 ÷ 249 = 0.06024096

20 ÷ 332 = 0.06024096


As you can see both numbers are equal and if you round it the unit rate will be 0.06¢ (maybe im not sure if you'll have to change the 15 since we moved the decimal in 2.49)

riadik2000 [5.3K]3 years ago
6 0
The unit rates are equal to one another.
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The stock's value dropped from $38.50 to $34.00.What negative number shows the change in value?
Liula [17]
I believe that would be -4.50 for problems like this you subtract then add the negative sign in front
i'm surprised you are in high school i did this in 6th grade
7 0
3 years ago
A triangle has side lengths of 33,56, and 65. Is it a right triangle? Explain.
soldier1979 [14.2K]
U can see if it is a right triangle bu using the pythagorean theorem (or however it is spelled)

a^2 + b^2 = c^2....where a and b are the legs and c is the hypotenuse (the largest side)

so lets sub our numbers in and see if they equal
33^2 + 56^2 = 65^2
1089 + 3136 = 4225
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5 0
3 years ago
Read 2 more answers
A teacher asks her students to write down the number of hours studied, rounded to the nearest half hour. She compiles the result
irina1246 [14]

Answer:1.50

Step-by-step explanation:None

5 0
3 years ago
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I need help on ratio of x-coordinates and ratio of y-coordinates
ad-work [718]

Answer:

Ratio of x-coordinates:

\frac{-1}{-2}=\frac{1}{2}

\frac{2}{4}=\frac{1}{2}

\frac{2}{4}=\frac{1}{2}

\frac{-2}{-4}=\frac{1}{2}

Ration of y-coordinates:

\frac{2.5}{5}=\frac{1}{2}

\frac{1}{2}=\frac{1}{2}

\frac{-2}{-4}=\frac{1}{2}

\frac{-2}{-4}=\frac{1}{2}

Step-by-step explanation:

The table is asking for the ratio of x-coordinates for each point (A, B, C and D) for both the image and pre-image.  The ratio is the image 'x' or 'y' value ÷ the pre-image 'x' or 'y' value.  Each ratio should be expressed in simplest form and should show the same pattern of dilation, or same scale factor.  In this case, the second figure is 1/2 the size of the original figure.  

5 0
3 years ago
Im stuck on this question, plz help
denis-greek [22]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the following :

40 metres covered in 6 seconds

Max speed attained after 6seconds

75 meters covered after 11 seconds

Average Speed for first 40 meters :

Speed = distance / time

Speed = 40m / 6s

Speed = 6.67m/s

To obtain the maximum speed :

Next (75 - 40) meters = 35 meters was covered in (11 - 6)seconds = 5 seconds

Speed at this point is maximum :

Hence, maximum speed = (35m / 5s) = 7m/s

Suppose, Manuel runs for an additional z seconds after reaching max speed :

Distance from starting line 6+z seconds after race started?

Distance after 6 seconds = 40 metres

Distance after z seconds = 7 * z

Total distance = (40 + 7z)

What is Manuel's distance from the starting line x seconds after the race started (provided x≥6x)?

Distance for first 6 seconds = 40 meters + distance covered after 6 seconds = (7 * (x-6))

40 + 7(x - 6)

3 0
3 years ago
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