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Andru [333]
3 years ago
7

Look at the screenshot

Mathematics
2 answers:
lozanna [386]3 years ago
7 0

Answer:

66.6666666667%

Step-by-step explanation:

(52/78)100

52/78 = 0.666666667

0.666666667(100) = 66.6666666667

BaLLatris [955]3 years ago
5 0

Answer:66.6 but if round 67%

Step-by-step explanation:

Because 52 ÷78 =66.6

So it's 67%

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alukav5142 [94]

Answer:

X= -0.4545

Step-by-step explanation:

YOU HAVE TO SUBTRACT .2Z FROM .4Z WHICH GETS YOU .2 ON THE RIGHT SIDE

THAT WOULD MEAN YOU HAVE TO CLEAR OUT THE SEVEN BY ADDING IT ON BOTH SIDES GETTING -1

THEN YOU WOULD HAVE -1=.2Z

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4 0
3 years ago
What is 45% of 36 feet
marta [7]
100% of 36 ft= 36 ft
50% of 36 ft= 18 ft
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3 years ago
A pharmaceutical company interviews 12 people for eight openings in the research department of the company. 7 of the 12 people a
bagirrra123 [75]

Answer:

7

Step-by-step explanation:

4 0
3 years ago
Research suggests that about 60% of CSU graduates started at a community college. In random samples of 100 CSU graduates, the pe
Nesterboy [21]

Answer:

The probability that in a random sample of 100 CSU graduates the error is within 5% of the population proportion of 60% is 0.6923.

Step-by-step explanation:

According to the Central limit theorem, if from an unknown population large samples of sizes <em>n</em> > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

 \mu_{\hat p}=p

The standard deviation of this sampling distribution of sample proportion is:

 \sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}

The information provided is:

<em>p</em> = 0.60

<em>n</em> = 100

As <em>n</em> = 100 > 30, the central limit theorem can be applied to approximate the sampling distribution of sample proportions.

The distribution of sample proportion is \hat p\sim N(0.60, 0.049^{2}).

Compute the probability that in a random sample of 100 CSU graduates the error is within 5% of the population proportion of 60% as follows:

P(|\hat p-\mu_{\hat p}|=0.05)=P(-0.05

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Thus, the probability that in a random sample of 100 CSU graduates the error is within 5% of the population proportion of 60% is 0.6923.

8 0
3 years ago
✍️ thought challenge...
MrRissso [65]

Answer:king author

Step-by-step explanation:

8 0
3 years ago
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