Question

What is the solution of this system of equations?

Answer 1

First we have to find the slopes, we need it in the slope intercept form for this:
2x - 3y = -5; this is the standard form
-3y = -2x - 5
Get rid of all those negatives, multiply eq by -1
3y = 2x + 5
Divide by 3 to get y
y = x + 
The slope of this equation (m1) is 

Answer 2

3x+5y=10 putting y= x+2 then
3x+5(x+2) =10
3x + 5x + 10 = 10
8x = 10 -10
x = 0/8
x= 0
and y= 0+2
then y = 2
co. are (0,2)