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3 years ago

Can you help me with a and b

Mathematics

1 answer:

tigry1 [53]3 years ago

3 0

Answer:

bro these college story problems getting deep

Step-by-step explanation:

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—7m<28 solve please hurry

mario62 [17]

Answer:

the answer is -4

Step-by-step explanation:

step 1: -7m<28

step 2: -7m÷ (-7)>28÷(-7)

step 3: m>28÷(-7)

step 4: m>-28÷7

step 5: m>-4

8 0

3 years ago

The first 32 whole numbers are evenly spaced around the circumference of a circle. Which number will be opposite of 26?

Ludmilka [50]

Answer:

"10"

Step-by-step explanation:

This is rather thinking "pictorially". Picture it.

You can match it with a round clock that has numbers 1 - 12 written on it.

So,

32 and 16 would be opposite of each other [top and bottom]. And, 1 - 15 would be on right side and 17 - 31 would be on left side.

Now,

Going counter-clockwise from 32, 26 would be the 6th number. Going counter-clockwise from 16, 10 would be the 6th number.

Hence, they would be opposite of each other.

10 would be opposite of 26

6 0

3 years ago

NEEEEEEEDDDD HELPPPPPPP ASAPPPPPPPPP

Anni [7]

The true statement about the diagram is (a) IJ ≅ JG

<h3>How to determine the true statement?</h3>

From the question, we understand that:

KH bisects line IG at point J

This means that:

Line segment IG is divided into two equal parts, and point J is the middle

So, we have:

IJ ≅ JG

Hence, the true statement about the diagram is (a) IJ ≅ JG

Read more about perpendicular bisector at:

brainly.com/question/24753075

#SPJ1

8 0

2 years ago

Add. -85.53+(-41.00) <br><br> A. -126.53<br> B. -44.47<br> C. 44.53<br> D. 126.47

Rashid [163]

The correct answer is A

7 0

3 years ago

Write and equation for the shift of the parent graph y=1/x

SashulF [63]

You can think of this equation as $\bf f(x)=\cfrac{1}{x}\implies f(x)=(x)^{-1}$

and thus apply the transformations to it as such

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\
% left side templates
\begin{array}{llll}
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}\\\\
--------------------\\\\$

$\bf \bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\$

$\bf \bullet \textit{ vertical shift by }{{ D}}\\
\left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\
\left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}$

1) D = 2, C = +3

2) D = -12, C = -2

3) C = +6, D = 3

4) C = -7, D = -7

7 0

3 years ago

Can you help me with a and b​

Can you help me with a and b