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AlladinOne [14]
3 years ago
6

A small airplane flies 1015 miles with an average speed of 290 miles per hour. 1.75 hours after the plane leaves, a Boeing 747 l

eaves from the same point. Both planes arrive at the same time; what was the average speed of the 747
Mathematics
1 answer:
expeople1 [14]3 years ago
3 0

Answer:

The average speed of the 747 was of 580 miles per hour.

Step-by-step explanation:

We use the following relation to solve this question:

v = \frac{d}{t}

In which v is the velocity, d is the distance and t is the time.

A small airplane flies 1015 miles with an average speed of 290 miles per hour.

We have to find the time:

v = \frac{d}{t}

290 = \frac{1015}{t}

290t = 1015

t = \frac{1015}{290}

t = 3.5

1.75 hours after the plane leaves, a Boeing 747 leaves from the same point. Both planes arrive at the same time;

The time of the Boeing 747 is:

t = 3.5 - 1.75 = 1.75

Distance of d = 1015, the velocity is:

v = \frac{d}{t} = \frac{1015}{1.75} = 580

The average speed of the 747 was of 580 miles per hour.

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Is the ordered pair (-2,-2) a solution to th fiction y= 3x-8
Tema [17]

Answer:-24

Step-by-step explanation:

You multiply your numbers without the - or the +

You check ehich number is bigger and you use it symbol for the answer

Example: 3x8= 24

-8 is bigger than 3 so you use it symbol

= -24

7 0
3 years ago
Margaret owns (5/6) of a section of land. She planted corn on (1/4) of her land. What fraction of the entire section is planted
yarga [219]

Answer:

3/5

Step-by-step explanation:

subtract the fractions then turn the decimal into a fraction.

5 0
2 years ago
A certain bridge arch is in the shape of half an ellipse 106 feet wide and 33.9 feet high. At what horizontal distance from the
nata0808 [166]

Answer:

The horizontal distance from the center is 49.3883 feet

Step-by-step explanation:

The equation of an ellipse is equal to:

\frac{x^2}{a^{2} } +\frac{y^2}{b^{2} } =1

Where a is the half of the wide, b is the high of the ellipse, x is the horizontal distance from the center and y is the height of the ellipse at that distance.

Then, replacing a by 106/2 and b by 33.9, we get:

\frac{x^2}{53^{2} } +\frac{y^2}{33.9^{2} } =1\\\frac{x^2}{2809} +\frac{y^2}{1149.21} =1

Therefore, the horizontal distances from the center of the arch where the height is equal to 12.3 feet is calculated replacing y by 12.3 and solving for x as:

\frac{x^2}{2809} +\frac{y^2}{1149.21} =1\\\frac{x^2}{2809} +\frac{12.3^2}{1149.21} =1\\\\\frac{x^2}{2809}=1-\frac{12.3^2}{1149.21}\\\\x^{2} =2809(0.8684)\\x=\sqrt{2809(0.8684)}\\x=49.3883

So, the horizontal distance from the center is 49.3883 feet

8 0
3 years ago
Laura says that the distance between (4,-2) and (4,-7) in the coordinate plane is equal to |-2-(-7)|units Ryan say that the dist
son4ous [18]

Answer:

Both are correct.

Step-by-step explanation:

In the point (4,-2) and (4,-7), the x-coordinates are same. So, the distance between these points is the absolute difference between the y-coordinates of these points.

Distance=|-2-(-7)|=5\text{ units}

So, Laura is correct.

In the point (2,3) and (-9,3), the y-coordinates are same. So, the distance between these points is the absolute difference between the x-coordinates of these points.

Distance=|2-(-9)|=|2+9|=11\text{ units}

So, Ryan is correct.

Hence, both are correct.

3 0
3 years ago
How many cubic feet are in cubic yard
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27 cubic feet..........
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