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Tpy6a [65]
3 years ago
10

If you help with the correct answer u are a god .pt2​

Mathematics
1 answer:
Brrunno [24]3 years ago
5 0

a. Answer:  D: (∞, ∞)

                   R: (-∞, ∞)

<u>Step-by-step explanation:</u>

Theoretical domain is the domain of the equation (without an understanding of what the x-variable represents).

Theoretical range is the range of the equation given the domain.

c(p) = 25p

There are no restrictions on the p so the theoretical domain is All Real Numbers.

Multiplying 25 by All Real Numbers results in the range being All Real Numbers.

a) D: (∞, ∞)

   R: (-∞, ∞)

*********************************************************************************

b. Answer:  D: (0, 200)

                    R: (0, 5000)

<u>Step-by-step explanation:</u>

Practical domain is the domain of the equation WITH an understanding of what the x-variable represents.

Practical range is the range of the equation given the practical values of the domain.

The problem states that p represents the number of cups.  Since we can't have a negative amount of cups, p ≥ 0.  The problem also states that Bonnie will purchase a maximum of 200 cups. So, 0 ≤ p ≤ 200

The range is 25p →  (25)0 ≤ (25)p ≤ (25)200

                             →      0   ≤  25p  ≤  5000

b) D: (0, 200)

   R: (0, 5000)

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marissa [1.9K]

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x = 90°

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A straight line has total 180° angle. A square has 4 sides of each 90° angle. A triangle is build up of 180° interior angle.

Workouts:

z + 90° + 50° = 180°

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=================

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Answer:

(a)g(n)=0.05\cdot 2^n

(b)g^{-1}(n)=\log_{2}20g(n)

(c)43 times

Step-by-step explanation:

<u>Part A</u>

The paper's thickness = 0.05mm

When the paper is folded, its width doubles (increases by 100%).

The thickness of the paper grows exponentially and can be modeled by the function:

g(n)=0.05(1+100\%)^n\\\\g(n)=0.05\cdot 2^n

<u>Part B</u>

<u />g(n)=0.05\cdot 2^n\\2^n=\dfrac{g(n)}{0.05}\\ 2^n=20g(n)\\$Changing to logarithm form, we have:\\\log_{2}20g(n)=n\\$Therefore:\\g^{-1}(n)=\log_{2}20g(n)<u />

<u />

<u>Part C</u>

If the thickness of the paper, g(n)=384,472,300,000 mm

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You must fold the paper 43 times to make the folded paper have a thickness that is the same as the distance from the earth to the moon.

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